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Pachacha [2.7K]
3 years ago
12

Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books

and y represent the number of nonfiction books
Mathematics
1 answer:
Llana [10]3 years ago
5 0
X and y are books
x is fiction
y=nonifiction

x+y=36


x=12+y

12+y+y=26
2y+12=26
minus 12
2y=14
divide 2
y=7


sub
x=12+y
x=12+7
x=19

nonfiction=7
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Ira Lisetskai [31]

Answer:   33

<u>Step-by-step explanation:</u>

The ratio of Adhy's to Ben's is 3:4 so let

Adhy = 3x

Ben = 4x

Since Ben = Adhy + 9

then   4x   =    3x    + 9

-->        x    =  9

So, Adhy = 3x  = 3(9)   = 27

     Ben   = 4x   = 4(9)   = 36

*************************************************************

The ratio of Ben's to Clayson's is 3:5

How do we get Ben's ratio of 3 equal to 36? <em>by multiplying by 12</em>

Ben  :  Clayson

<u>3 x 12</u>    <u>5 x 12</u>

 36          60

So, Clayson = 60

***********************************************************

The difference between Adhy and Clayson is:

Clayson - Adhy

   60     -    27    = 33

3 0
3 years ago
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salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

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Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

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4 0
3 years ago
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Answer:

15) a) 8

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3 years ago
There are 50 read beans and 50 white beans in a bag . The first bean selected is red . The red bean is returned to the bag . Wha
andrew11 [14]

Answer:

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2 years ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

y=5^{x}

y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

8 0
3 years ago
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