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3 years ago

Jordan and Beth are mixing yellow and blue paint to make green paint.

Mathematics

2 answers:

Nastasia [14]3 years ago

5 0

Answer:

HI RACHEL

Step-by-step explanation:

so you do 1 + 1 which equalls to -8

then you do 7 - 9 which qualls 67

LOOL

nata0808 [166]3 years ago

4 0

Answer:

Jordan

Step-by-step explanation:

Jordan 5:2 -> 10:4, 15:6 20:8 25:10 50:20 60:24 70:28

Beth 18:7-> 36:14 54:21 72:28

When Both of them add 28 of BLUE paint, Jordan adds only 70 yellow paint, while Beth uses 72 yellow paint. This would make Jordan's green darker.

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Translate and solve: fifty times n is at most 500.<br><br> Give your answer in interval notation.

andrey2020 [161]

Answer: (-infinity,10]

Step-by-step explanation: 50n is less than or equal to 500. So, treat the less than or equal to sign as an equal sign. Then do like regular and divide 500 by 50 to get ten on the right while N stays on the left. To get n is greater than or equal to 10!

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3 years ago

Is this adjacent or vertical

vazorg [7]

Is there supposed to be an image? Adjacent is adjoining, so like touching each other. Vertical is "up". Horizontal is "side"

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3 years ago

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ladessa [460]

Step-by-step explanation:

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3 years ago

Given and proof with the figure below. <br> Complete the following proof

nevsk [136]

Answer:

2 step proof, Subtraction Property

Step-by-step explanation:

This one is pretty easy if you know a shortcut. Addition, Subtraction, Multiplication, and division properties.

Think about it this way. Subtract angle 1 from QUS. Then subtract angle 2 from RUT. Knowing RUT is equal to QUS means that the differences are the same.

Don't know if this is right or not but hope this helps.

Here's my work

7 0

3 years ago

I'll mark brainliest just tell me how to.

IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

$\frac{( {x}^{5}y {z}^{4} )^{3} }{ {x}^{3} yz} = {x}^{a} {y}^{b} {z}^{c} \\ \\ \frac{ {x}^{5 \times 3}y^{3} {z}^{4 \times 3} }{ {x}^{3} yz} = {x}^{a} {y}^{b} {z}^{c} \\ \\ \frac{ {x}^{15}y^{3} {z}^{12} }{ {x}^{3} yz} = {x}^{a} {y}^{b} {z}^{c} \\ \\ {x}^{15 - 3} {y}^{3 - 1} {z}^{12 - 1} = {x}^{a} {y}^{b} {z}^{c} \\ \\ {x}^{12} {y}^{2} {z}^{11} = {x}^{a} {y}^{b} {z}^{c} \\ \\ equating \: like \: terms \: from \: both \: sides \\ \\ {x}^{12} = {x}^{a} \: \implies \: a = \boxed{ 12}\\ \\ {y}^{2} = {y}^{b} \: \implies \: b = \boxed{ 2} \\ \\ {z}^{11} = {z}^{c} \: \implies \: c = \boxed{ 11}$

3 0

3 years ago