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Gekata [30.6K]
3 years ago
5

I'll mark brainliest just tell me how to.

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

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Step-by-step explanation:

7 0
2 years ago
Luiza wants to go on a popular talent TV show. In order to be accepted, her audition must get at least 60%
Elena-2011 [213]

We cannot reject the null hypothesis as the p value is less than 0.01.

<h3>How to illustrate the hypothesis?</h3>

From the information given, Luiza wants to go on a popular talent TV show and in order to be accepted, her audition must get at least 60% positive votes from the people in the crowd.

The observed outcome also has a probability less than 1% under the tested hypothesis. Based on the information, the test statistic will be - 1.58.

After this, this will be checked under the standard normal distribution table where the p value will be 0.0571.

Based on this information, we cannot reject the null hypothesis as the p value is less than 0.01.

In conclusion, the correct option is that we cannot reject the hypothesis.

Learn more about hypothesis on:

brainly.com/question/25263462

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3 0
1 year ago
There are 10 marbles in a bag: 1 blue, 4 yellow, 3 red, and 2 white. If you choose a marble at random, which is the probability
Eduardwww [97]

Answer:

8/10

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6 0
3 years ago
Please help me with the below question.
inessss [21]

Pick any two points on the line.

• if x = 1, then y = 4 and z = 3

• if x = -1, then y = 7 and z = 2

Observe that P is not on the given line.

The vector from (1, 4, 3) to P points in the same direction as

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and the vector from (-1, 7, 2) to P points in the same direction as

(0, 5, 2) - (-1, 7, 2) = (1, -2, 0)

The cross product of these vectors is

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and is normal to the plane we want to find. Since the plane contains P, the equation of the plane is

(-2, -1, 1) • (x - 0, y - 5, z - 2) = 0   ⇒   2x + y - z = 3

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1 year ago
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Galina-37 [17]

Answer:

(x+7)(x-7)

Mark my answer as Brainlist.

8 0
3 years ago
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