The required mass of aquarium when it is half full of water is 10 kg.
Mass of the aquarium = 5kg
Length = 25 cm, width = 20 cm and height = 10 cm(when half filled)
<h3>What is volume?</h3>
Volume, is defined as the ratio of the mass of object to its density.
Since, density of the water = 1000 Kg/m³
Now Mass of the water = Volume x density
= 25/100 x 20/100 x 10/100 x 1000
= 0.005 x 1000
= 5 kg
Now, the total mass of the aquarium when half filed by water.
= mass of water + mass of aquarium
= 5 + 5
= 10 kg
Thus, the required mass of aquarium when it is half full of water is 10 kg.
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Answer:
144 u²
Step-by-step explanation:
first we need to find lateral area
La=Ph
LA=(12)(11)
LA= 132 u²
SA= Ph + 2B
SA= 132 + 2(6)
SA= 144 u²
Answer:
d
Step-by-step explanation:
Hello there! ^-^
To solve, do the following.
2n + 6 = 8n and 6n - 2 = 4n
I think you can take it from here ;)
If not just simply message me
