Answer
Step-by-step explanation:
227.49 x 1.09 = 247.96
You are given the length of a rectangular prism of 3x^2, width of 2x and height of x^2 + 3x +5. You are required to find the volume of a rectangular prism. Using the equation V = l x w x h, we multiply the three dimensions.
V = l x w x h
V = (3x^2)(2x)( x^2 + 3x +5)
V = 2x (3x^4 + 9x^3 + 15x^2)
V = 6x^5 + 18x^4 + 30x^3
The volume of the rectangular prism is 6x^5 + 18x^4 + 30x^3.
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
24+8 = 30
30 - 12 = 18
18-9 = 8
There are 8 cards left in the stack
let's firstly convert the mixed fractions to improper fractions, and then add.
![\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{2\frac{5}{6}}\implies \cfrac{2\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{17}{6}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{17}{6}\implies \stackrel{\textit{we'll use the LCD of 12}}{\cfrac{(3)13~~+~~(2)17}{12}}\implies \cfrac{39+34}{12}\implies \cfrac{73}{12}\implies 6\frac{1}{12}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B13%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B5%7D%7B6%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%206%2B5%7D%7B6%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B17%7D%7B6%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B13%7D%7B4%7D%2B%5Ccfrac%7B17%7D%7B6%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20the%20LCD%20of%2012%7D%7D%7B%5Ccfrac%7B%283%2913~~%2B~~%282%2917%7D%7B12%7D%7D%5Cimplies%20%5Ccfrac%7B39%2B34%7D%7B12%7D%5Cimplies%20%5Ccfrac%7B73%7D%7B12%7D%5Cimplies%206%5Cfrac%7B1%7D%7B12%7D)
