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schepotkina [342]
3 years ago
13

A binomial probability experiment is conducted with given parameters. Compute the probability of x successes in the n independen

t trials of the experiment.
N=9, p=0.9, x=6
Mathematics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

0.044

Step-by-step explanation:

n=9,p=0.9, x =6.

Apply Binomial probability we get

Sum P(x)=C(n,x) p^{x} (1-p)^{n-x} for x=6

Putting in the formula ,

we get

P(x) = C(9,6) 0.9^{6} 0.1^{3}

84 X 0.531441 X 0.001

= 0.044

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Look at the figure which step should be taken next to construct a line parallel to AB
FinnZ [79.3K]
My answer is the 2nd option.

Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.

Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB. 
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3 years ago
Solve 37+z≤54. Graph the solution.
iragen [17]

Answer:

z ≤ 17

Step-by-step explanation:

Step 1: Subtract 37 from both sides.

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3 0
3 years ago
Read 2 more answers
Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

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3 years ago
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3x + (x - 0.75x)
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