Please help im timed how would you solve 17=w/4?
2 answers:
You might be interested in
- Solve for x.
Okay, so from the given figure we can see that, < FAE & < FAB forms a linear pair. In a linear pair, the 2 angles will together sum up to 180°. So,
- < FAE = 4x°
- < FAB = 2x°
__________________
From the explanation, we can understand that,
Sum of the linear pair = 180°
< FAE + < FAB = 180°
4x° + 2x° = 180°
6x° = 180°
x° = 180 ÷ 6
x = <u>3</u><u>0</u><u>°</u><u>.</u>
__________________
- The value of x will be<em><u> 30°</u></em> (3rd option).
__________________
<u>NOTE</u> : Here, the lesser than symbol ( < ) stands for 'angle'.
Answer:
The equation contains exact roots at x = -4 and x = -1.
See attached image for the graph.
Step-by-step explanation:
We start by noticing that the expression on the left of the equal sign is a quadratic with leading term , which means that its graph shows branches going up. Therefore:
1) if its vertex is ON the x axis, there would be one solution (root) to the equation.
2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.
3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.
So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:
We recall that the x-position of the vertex for a quadratic function of the form is given by the expression:
Since in our case and
, we get that the x-position of the vertex is:
Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:
This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).
We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the . Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.
When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):
The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.
Then, the two roots are: x = -1 and x = -4.
