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MAXImum [283]
3 years ago
10

Which expression represents the product of q and 8, divided by 4?

Mathematics
1 answer:
Julli [10]3 years ago
5 0
The answer is the second choice. Hope this helps!
You might be interested in
What is the value of X? What is the measure of angle ABC?
gizmo_the_mogwai [7]

Answer:

x=14

Step-by-step explanation:

create an equation out of it. 4x+2x-6=90. Or 6x=84

4 0
3 years ago
If the length of a rectangular field is twice the width and the perimeter is 24. Write an equation that an be used to solve for
Sedbober [7]
If we use the width as x we have 2x with both widths and 4x with both lengths. So 6x=24 and x=4. So length is 8 and width is 4.
7 0
3 years ago
Set up, but do not evaluate, the integral that represents the length of the curve given by x = 1 + 3t^2, y = 4 + 2t^3 over the i
kherson [118]

L

=

∫

t

f

t

i

√

(

d

x

d

t

)

2

+

(

d

y

d

t

)

2

d

t

. Since  

x

and  

y

are perpendicular, it's not difficult to see why this computes the arclength.

It isn't very different from the arclength of a regular function:  

L

=

∫

b

a

√

1

+

(

d

y

d

x

)

2

d

x

. If you need the derivation of the parametric formula, please ask it as a separate question.

We find the 2 derivatives:

d

x

d

t

=

3

−

3

t

2

d

y

d

t

=

6

t

And we substitute these into the integral:

L

=

∫

√

3

0

√

(

3

−

3

t

2

)

2

+

(

6

t

)

2

d

t

And solve:

=

∫

√

3

0

√

9

−

18

t

2

+

9

t

4

+

36

t

2

d

t

=

∫

√

3

0

√

9

+

18

t

2

+

9

t

4

d

t

=

∫

√

3

0

√

(

3

+

3

t

2

)

2

d

t

=

∫

√

3

0

(

3

+

3

t

2

)

d

t

=

3

t

+

t

3

∣

∣

√

3

0

=

3

√

3

+

3

√

3

=6The arclength of a parametric curve can be found using the formula:  

L

=

∫

t

f

t

i

√

(

d

x

d

t

)

2

+

(

d

y

d

t

)

2

d

t

. Since  

x

and  

y

are perpendicular, it's not difficult to see why this computes the arclength.

It isn't very different from the arclength of a regular function:  

L

=

∫

b

a

√

1

+

(

d

y

d

x

)

2

d

x

. If you need the derivation of the parametric formula, please ask it as a separate question.

We find the 2 derivatives:

d

x

d

t

=

3

−

3

t

2

d

y

d

t

=

6

t

And we substitute these into the integral:

L

=

∫

√

3

0

√

(

3

−

3

t

2

)

2

+

(

6

t

)

2

d

t

And solve:

=

∫

√

3

0

√

9

−

18

t

2

+

9

t

4

+

36

t

2

d

t

=

∫

√

3

0

√

9

+

18

t

2

+

9

t

4

d

t

=

∫

√

3

0

√

(

3

+

3

t

2

)

2

d

t

=

∫

√

3

0

(

3

+

3

t

2

)

d

t

=

3

t

+

t

3

∣

∣

√

3

0

=

3

√

3

+

3

√

3

=

6

√

3

Be aware that arclength usually has a difficult function to integrate. Most integrable functions look like the above where a binomial is squared and adding the two terms will flip the sign of the binomial.    

Be aware that arclength usually has a difficult function to integrate. Most integrable functions look like the above where a binomial is squared and adding the two terms will flip the sign of the binomial.

8 0
3 years ago
Which expression is equivalent to<br> 6 OF<br> 5y3<br> (5)<br> Ο Ο<br> 125y3<br> 125y5
ValentinkaMS [17]

Answer:

✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

6 0
2 years ago
BRAINLIEST can someone please help!!!!!
Zielflug [23.3K]

I don't know about the first one but for the second one:

{2}^{3x + 2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow {2}^{3x}  {2}^{2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x} ( 4  - 1) = 48 \\ \Leftrightarrow 3 \times  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x}  = 16 \\ \Leftrightarrow  {2}^{3x}  =  {2}^{4}  \\ \Leftrightarrow 3x = 4\Leftrightarrow x =  \frac{4}{3}

4 0
3 years ago
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