Question

What is the length of the hypotenuse, x, if (20,21,x) is a Pythagorean triple?

Answer 1

Answer:

29

Step-by-step explanation:

$(20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29$

Answer 2

Answer:

B. 29

Step-by-step explanation:

Use Pythagoras theorem.

a² + b² = c²

x is the hypotenuse.

20² + 21² = x²

400 + 441 = x²

841 = x²

√841 = √(x²)

29 = x