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Kruka [31]
3 years ago
11

Please answer with an explanation on why whoever's method is wrong thank you

Mathematics
1 answer:
tatiyna3 years ago
7 0
Brandon’s method is incorrect because if we continue the pattern, 9 times 1/2 is 4.5. It’s obvious that the square root of 9 is 3. Similarly, the square root of 16 is 4, but 16 times 1/2 is 8. Any number you will try after that won’t work.
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How many solutions do the TWO equations have?
Nadya [2.5K]

Answer:

Below.

Step-by-step explanation:

15y + 12x = 18

5y + 4x = 6

The  second equations is the first times 3 so they are basically the same.

Infinite Solutions.

2x+ 3y= 12

-6y= 4x-24          Rearranging the second equation:

-4x - 6y = -24      Multiplying the first equation by 2:

4x + 6y = 24      

- we see that the last equation is -1 * previous equation.

So there are infinite solutions.

7 0
3 years ago
What is a number that is six hundred thousand more than the number?
Licemer1 [7]

Answer:

If you are asking for an equation sentence then I can give you one!

Step-by-step explanation:

N> 600,000

3 0
4 years ago
Do you know what the answer to this question is?
Y_Kistochka [10]

I think the answer is 4

3 0
4 years ago
find two positive real numbers such that they sum to 108 and the product of the first times the square of the second is a maximu
topjm [15]

The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.

Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.

Let us consider the two positive real numbers as x and y. Then, their sum is written as,

x+y=108

Then, y=108-x

And the product is written as,

P=xy²

Substitute value of y in the above equation, we get,

\begin{aligned}P&=x(108-x)^2\\&=x(11664-216x+x^2)\\&=11664x-216x^2+x^3\\&=x^3-216x^2+11664x\end{aligned}

Now, differentiate P with respect to x, and we get,

\begin{aligned}\frac{dP}{dx}&=3x^2-432x+11664\\&=x^2-144x+3888\end{aligned}

Solving the above equation to zero, we get,

\begin{aligned}x^2-144x+3888&=0\\x^2-36x-108x+3888&=0\\x(x-36)-108(x-36)&=0\\(x-108)(x-36)&=0\\x&=\text{108 or 36}\end{aligned}

Substitute values of x in y=108-x, to get values of y.

If we substitute x=108, we get the y value as zero which doesn't give the required solution.

But, if we substitute x=36, we get,

\begin{aligned}y&=108-36\\y&=72\end{aligned}

Thus, the two positive numbers are 36 and 72.

To know more about positive numbers:

brainly.com/question/1635103

#SPJ4

4 0
1 year ago
Plz solve!!!!! I will give 25 points and brainliest!! and plz, no tiny links<br> 1 3/7*2/5
Airida [17]

Answer:

10/7*2/5= 20/35=4/7

5 0
3 years ago
Read 2 more answers
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