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tresset_1 [31]
3 years ago
8

Chet and Wesley sold gift wrap for a school fund-raiser.

Mathematics
1 answer:
atroni [7]3 years ago
4 0
I believe the answer is 5/14
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Please answer this the best
dexar [7]

Answer:

6 because they are 6 sq apart

Step-by-step explanation:

7 0
3 years ago
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Please help me have to turn it in before 5:00
attashe74 [19]

Answer:

20 team members

Step-by-step explanation:

5 liters is 5000 milliliters, so you divide 5000 by 250, and you get 20.

4 0
3 years ago
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Mr. Martin’s math test which is worth 100 points has 29questions. Each problem is worth 2points or 5 points. X represents number
adell [148]

Answer:there are 14 5point problems and 15 2point problems on the test.

Step-by-step explanation:

x represents number of 5 point questions and y represents questions worth 2 points.

The total number of questions in the test is 29. It means that

x + y = 29

x = 29 - y

Mr. Martin’s math test is worth 100 points. It means that

5x + 2y = 100 - - - - - - - - -1

Substituting x = 29 - y into equation 1, it becomes

5(29 - y) + 2y = 100

145 - 5y + 2y = 100

- 5y + 2y = 100 - 145

- 3y = - 45

y = - 45/-3

y = 15

x = 29 - y = 29 - 15

x = 14

3 0
3 years ago
25 less than twice a number is equal to the number. What is the number?
belka [17]

Step-by-step explanation:

x = the number

2x - 25 = x

2x = x + 25

x = 25

8 0
2 years ago
Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt

= e^{0.035\times4}\times4,122.4

= $4,742

8 0
2 years ago
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