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3 years ago

The egyptian has a base with a length of 230 m,width m, and a height of 147 m. what is the surface area of the pyramid

1 answer:

6 0

A unit cube is simply a cube measuring one inch, one centimeter, one foot, or whatever unit of measurement you are using, on all sides. ... If you look carefully, you will see that the volume of therectangular prism is a function of multiplying the length the width the height. ... First find the area of thebase. does that help

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Think about the properties of a square. Is a square also a rhombus? Is it also a rectangle? Answer each question and explain you

djyliett [7]

Answer:

Properties of rhombus

. all the properties of a parallelogram( apply the ones that matter hair are parallel sides opposite angles congruent and consecutive angles are supplementary)

. all sides are congruent by definition

. the diagonals bisect the angles

. the diagonals are perpendicular bisectors of each other

Properties of rectangle

. all the properties of parallelogram apply (the ones that matter hair are parallel sides, opposite sides are congruent, and diagonals bisect each other)

. all angles are right angles by definition

. the diagonals are congruent

Properties of square

. all the properties of a rhombus apply( the ones that matter have a parallel sides diagonals are perpendicular bisector of each other and diagonals bisect the angles)

. All the properties of rectangle apply (the only one that matter where is diagonals are congruent)

. All angles are right angles by definition

Hope it will help you

Step-by-step explanation:

4 0

3 years ago

Find the sum of 67.008 and 3.8

zysi [14]

Answer:

69.808

Step-by-step explanation:

69.808

4 0

3 years ago

Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the

babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

$d=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2} }$

DC:

D(-2,-1) C(-1,2)

$d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2} } \\d=\sqrt{10} =3.16$

CF:

C(-1,2) F(1,1)

$d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2} } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24$

F(1,1) E(2,-2)

$d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16$

E(2,-2) D(-2,-1)

$d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2} } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\$

3.16+2.24+3.16+4.12= 12.68

4 0

2 years ago

Kelly rows a boat at the rate of 7040 yards per hour. How fast did Kelly row in miles?

irakobra [83]

Answer:

4 mph

Step-by-step explanation:

yard → mile = divide the length value by 1760

7040 / 1760 = 4 miles per hour

6 0

3 years ago

A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an a

Scrat [10]

Answer:

The answer is (C) 8

Step-by-step explanation:

First, let's calculate the length of the side of the square.

$A_{square}=a^2$ , where $a$ is the length of the side. Now, let's try to build the square. First we need to find a point which distance from (0, 0) is 10. For this, we can use the distance formula in the plane:

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ which for $x_1=0$ and $y_1 = 0$ transforms as $d=\sqrt{(x_2)^2 + (y_2)^2}$ . The first point we are looking for is connected to the origin and therefore, its components will form a right triangle in which, the Pythagoras theorem holds, see the first attached figure. Then, $x_2$ , $y_2$ and 10 are a Pythagorean triple. From this, $x_2= 6$ or $x_2=8$ while $y_2= 6$ or $y_2=8$ . This leads us with the set of coordinates:

$(\pm 6, \pm 8)$ and $(\pm 8, \pm 6)$ . (A)

The next step is to find the coordinates of points that lie on lines which are perpendicular to the lines that joins the origin of the coordinate system with the set of points given in (A):

Let's do this for the point (6, 8).

The equation of the line that join the point (6, 8) with the origin (0, 0) has the equation $y = mx +n$ , however, we only need to find its slope in order to find a perpendicular line to it. Thus,

$m = \frac{y_2-y_1}{x_2-x_1} \\m = \frac{8-0}{6-0} \\m = 8/6$

Then, a perpendicular line has an slope $m_{\bot} = -\frac{1}{m} = -\frac{6}{8}$ (perpendicularity condition of two lines). With the equation of the slope of the perpendicular line and the given point (6, 8), together with the equation of the distance we can form a system of equations to find the coordinates of two points that lie on this perpendicular line.

$m_{\bot}=\frac{6}{8} = \frac{8-y}{6-x}\\ 6(6-x)+8(8-y)=0$ (1)

$d^2 = \sqrt{(y_o-y)^2+(x_o-x)^2} \\(10)^2=\sqrt{(8-y)^2+(6-x)^2}\\100 = \sqrt{(8-y)^2+(6-x)^2}$ (2)

This system has solutions in the coordinates (-2, 14) and (14, 2). Until here, we have three vertices of the square. Let's now find the fourth one in the same way we found the third one using the point (14,2). A line perpendicular to the line that joins the point (6, 8) and (14, 2) has an slope $m = 8/6$ based on the perpendicularity condition. Thus, we can form the system:

$\frac{8}{6} =\frac{2-y}{14-x} \\8(14-x) - 6(2-y) = 0$ (1)

$100 = \sqrt{(14-x)^2+(2-y)^2}$ (2)

with solution the coordinates (8, -6) and (20, 10). If you draw a line joining the coordinates (0, 0), (6, 8), (14, 2) and (8, -6) you will get one of the squares that fulfill the conditions of the problem. By repeating this process with the coordinates in (A), the following squares are found:

(0, 0), (6, 8), (14, 2), (8, -6)

(0, 0), (8, 6), (14, -2), (6, -8)
(0, 0), (-6, 8), (-14, 2), (-8, -6)
(0, 0), (-8, 6), (-14, -2), (-6, -8)

Now, notice that the equation of distance between the two points separated a distance of 10 has the trivial solution $(\pm10, 0)$ and $(0, \pm10)$ . By combining this points we get the following squares:

(0, 0), (10, 0), (10, 10), (0, 10)
(0, 0), (0, 10), (-10, 10), (-10, 0)
(0, 0), (-10, 0), (-10, -10), (0, -10)
(0, 0), (0, -10), (-10, -10), (10, 0)

See the attached second attached figure. Therefore, 8 squares can be drawn

8 0

2 years ago