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3 years ago

What are 2 ways to solve 20=-5(-3+x)

2 answers:

s2008m [1.1K]3 years ago

5 0

1) 20 = -5(-3+x)
20/-5 = -3 + x
-4 = -3 + x
-4 + 3 = x
x = -1
2)20 = -5(-3 + x)
20 = 15 - 5x
20 - 15 = - 5x
5 = -5x
5/-5 = x
x = -1

lions [1.4K]3 years ago

3 0

1) First way:

$-5(-3+x) = 20$

=> $15 - 5x = 20$

=> $-5x = 20 -15$

=> $-5x = 5$

=> $x = 5/-5$

=> $x = -1$

2) Second way:

$-5(-3+x)=20$

=> $-3+x = 20/-5$

=> $- 3 + x = -4$

=> $x = -4 + 3$

=> $x = -1$

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3 years ago

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2 years ago

Solve1 over 25 = 5^x ^+ 4. <br> x = -7/2<br> x = −6 <br> x = 9/2 <br> x = 2

Basile [38]

The equation seems to be

   1
-------- = 5 ^ (x + 4)
25

In that case, this is the solution, stept by step:

1) factor 25: 25 = 5^2

      1
=> ----------- = 5^(x + 4)
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2) invert 5^2

=> 5^(-2) = 5^(x+4)

3) Given that the bases are equal, the exponents also have to be equal:

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3) transpose +4:

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3 years ago