Help on math plz help
2 answers:
You might be interested in
On the number line, 3 and 11 are the numbers that are a distance of 4 units from 7..
On there are two types of numbers one is a positive and the other is a negative number. These two are separated by the number zero which is known as the origin. Positive numbers are on the right side of the origin and negative numbers are on the left side of the origin on the number line.
We have been asked the numbers which are a distance of 4 units from 7 on the number line.
For that, we will first add 4 to the number 7, that is,
4 + 7 = 11
Thus, number 11 is a distance of 4 units from 7 on the number line if we move to the right side from 7.
Now we will subtract 4 from the 7 we will get,
7-4 = 3
Thus, Number 3 is a distance of 4 units from 7 on the number line if we move to the left side from 7.
Hence 3 and 11 are the numbers that are a distance of 4 units from 7 on the number line.
Learn more about the number line here: brainly.com/question/77754
#SPJ9
To change a mixed fraction, you'd multiply the number upfront, times the denominator, and then add that product to the numerator
that IS the new numerator, and you keep the denominator
thus
that IS the new numerator, and you keep the denominator
thus
SA = 900cm^2
SA = 6×(s^2), where "s" is one side or edge of each square surface face
900 = 6s^2
150 = s^2
So each side is
The volume (V) of a cube is:
SA = 6×(s^2), where "s" is one side or edge of each square surface face
900 = 6s^2
150 = s^2
So each side is
The volume (V) of a cube is: