Let A = { 0 , 2 , 4 , 6 } , B = { 1 , 2 , 3 , 4 , 5 } , and C = { 1 , 3 , 5 , 7 } . Find { x ∣ x ∈ B or x ∈ C } .
EastWind [94]
Answer:
{1, 2, 3, 4, 5, 7}
Step-by-step explanation:
x in B or C is ...
B ∪ C = {1, 2, 3, 4, 5, 7}
Answer:
lila added 1/12 more than fiona
Step-by-step explanation:
find GCF (12), multiply amounts added accordingly
lila added 9/12 (multiply 3/4 by 3)
fiona added 2/3 (multiply 2/3 by 4)
We want to replace x with 2x in the original equation
g(2x) = 3(2x) -5
We can multiply 3 and 2x to simplify this, which will give us 6x
g(2x) = 6x - 5
Answer: 0.0386
Step-by-step explanation:
Given: The population of 400 tall women has a mean height
of 179.832 cm and a standard deviation
of 12.192 cm.
Let X be a random variable that represents the height of woman.
Sample size : n= 50
The probability that the mean for this sample group is above 182.88 will be :
![P(\overline{X}>182.88)\\\\=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{182.88-179.832}{\dfrac{12.192}{\sqrt{50}}})\\\\ =P(Z>1.7678)\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28%5Coverline%7BX%7D%3E182.88%29%5C%5C%5C%5C%3DP%28%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3E%5Cdfrac%7B182.88-179.832%7D%7B%5Cdfrac%7B12.192%7D%7B%5Csqrt%7B50%7D%7D%7D%29%5C%5C%5C%5C%20%3DP%28Z%3E1.7678%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C1.7678%29%5C%5C%5C%5C%3D1-0.9614%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20p-value%20table%7D%5D%5C%5C%5C%5C%3D%200.0386)
Hence, Required probability = 0.0386
So there isn’t an exact answer however, this is what I got: 0.006345177664975
