Help please don’t answer if you don’t know also I’ll give brainliest

Mathematics

2 answers:

DerKrebs [107]3 years ago

7 0

Answer:

3x+4x+3x=12-8

10x=4

x=4/10

x=2/5

x= o.4

hope you have a nice day

( •_•)>⌐■-■ ( ⌐■_■)

-kay

egoroff_w [7]3 years ago

5 0

Answer:

10x=4

x=4/10

x=2/5

Step-by-step explanation:

You might be interested in

A rectangle has an area of 20 ft.² in a similar rectangle has an area of 180 ft.² what is the ratio of areas of the similar

vovikov84 [41]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{cccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s^2}{s^2}=\cfrac{20}{180}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{20}{180}\implies \cfrac{s}{s}=\sqrt{\cfrac{20}{180}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{20}}{\sqrt{180}}\implies \cfrac{s}{s}=\cfrac{2\sqrt{5}}{6\sqrt{5}}\implies \cfrac{s}{s}=\cfrac{2}{6}\implies \cfrac{s}{s}=\cfrac{1}{3}$

6 0

4 years ago

Help plzzzzzzzzzzzzzzzzzzzzz

prohojiy [21]

Answer:

c = ${\boxed{\boldsymbol{29}}}$ km

Step-by-step explanation:

Here's the required formula to find the missing side of triangle by pythagoras theorem :

${\longrightarrow{\pmb{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}}}$

$\purple\star$ a = 20 km
$\purple\star$ b = 21 km
$\purple\star$ c = ?

Substituting all the given values in the formula to find the third side of triangle :

$\begin{gathered} \quad{\longrightarrow{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{{(20)}^{2} + {(21)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(20 \times 20) + (21 \times 21) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(400) + (441) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{400 + 441 = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{841= {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{c = \sqrt{841}}}} \\ \\ \quad{\longrightarrow{\sf{\underline{\underline{\purple{c = 29 \: km}}}}}}\end{gathered}$