1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashutka [201]
2 years ago
13

Purchased a DVD player on sale. The original selling price was ​$. The sale price was ​$.

Mathematics
1 answer:
gregori [183]2 years ago
8 0

what are the prices?

You might be interested in
The number of people in thousands who own a cell phone is a function of the time in years starting in 1990 where p(t) = 20(1.075
Julli [10]
Try to look it up tbh
4 0
3 years ago
3X-8 &lt; 16<br> Solution is
OLga [1]

Answer: x<8

interval notation is ( -∞,8)

Step-by-step explanation:

x<8

interval notation is ( -∞,8)

6 0
2 years ago
What is 1 + 1<br><br> Please give a detailed answer and I’ll crown
Ksivusya [100]

Answer:

1+1+2

1/10x10=1

1/10x10=1

(1/10x10)+(1/10x10)+2

or...

0.5x2=1

0.5x2=1

(0.5x2)+(0.5x2)=2

hope this helps lol

6 0
2 years ago
Read 2 more answers
Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari
Ulleksa [173]

Answer:

(a)E[X+Y]=E[X]+E[Y]

(b)Var(X+Y)=Var(X)+Var(Y)

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).

Since f(X,Y)=X+Y

E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).

Let us look at the first of these sums.

\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].

Similarly,

\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].

Combining these two gives the formula:

\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)

Therefore:

E[X+Y]=E[X]+E[Y] \text{  as required.}

(b)We  want to show that if X and Y are independent random variables, then:

Var(X+Y)=Var(X)+Var(Y)

By definition of Variance, we have that:

Var(X+Y)=E(X+Y-E[X+Y]^2)

=E[(X-\mu_X  +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2  +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2  +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2  +E[Y- E(Y)]^2+2Cov (X,Y)

Since X and Y are independent, Cov(X,Y)=0

=Var(X)+Var(Y)

Therefore as required:

Var(X+Y)=Var(X)+Var(Y)

7 0
3 years ago
Help please :))))))))​
docker41 [41]

Answer: 35/24 is the answer for the first part only.

Use calculator soup on google search to answer the rest.

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Divide the binomial by the monomial to find the quotient -36x^4y + 144x^2 y^6/ -4x^2y
    13·2 answers
  • 6/12 + 1/3 with steps?
    6·2 answers
  • What values of x will give a total area of 1000ftsquare? 2000ftsquare
    8·1 answer
  • Determine the fraction of the total interest owed after the fourth month of a 12 month loan
    15·1 answer
  • At which root does the graph of f(x) = (x – 5)3(x + 2)2 touch the x-axis?
    8·1 answer
  • How many gallons of water did niles pour into the tank each minute? Please help me asap​
    7·1 answer
  • WHAT WOULD THIS BEEEEEEE!!!!
    8·2 answers
  • CAN SOMEONE HELP ME PLSS IM FAILING AND I RLLY NEED HELP HELP ASAP HELP MATH MATH MATH HELPPPPPPPPPP
    14·1 answer
  • a cleaning service charges an hourly rate plus a flat fee of $15 for supplies. philip uses the service for 3.5 hours for his spr
    8·1 answer
  • I know im terrible at math, dont tell me lol i need help this app is making this so much easier- 25 pts! fake answers will be de
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!