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Airida [17]
3 years ago
14

A random sample of 157 recent donations at a certain blood bank reveals that 86 were type A blood. Does this suggest that the ac

tual percentage of type A donations differs from 40%, the percentage of the population having type A blood? Carry out a test of the appropriate hypotheses using a significance level of 0.01. State the appropriate null and alternative hypotheses.
Mathematics
1 answer:
posledela3 years ago
6 0

Answer: Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.

Step-by-step explanation:

Since we have given n = 157

x = 86

So, \hat{p}=\dfrac{x}{n}=\dfrac{86}{157}=0.55

and we have p = 0.4

So, hypothesis would be

H_0:p=\hat{p}\\\\H_a:p\neq \hat{p}

Since there is 1% level of significance.

So, test statistic value would be

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.55-0.40}{\sqrt{\dfrac{0.4\times 0.6}{157}}}\\\\z=\dfrac{0.15}{0.039}\\\\z=3.846

and the critical value at 1% level of significance , z = 2.58

Since 2.58<3.846.

So, we reject the null hypothesis.

Hence, Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.

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Answer:

5

Step-by-step explanation:

The equation of a straight line is :

y=mx+c

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so if m equals 5 then the gradient is 5

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2 years ago
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Step-by-step explanation:

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If a pine tree grows 4 inches per year, how long will it take for the tree to reach a height of 13 feet?
attashe74 [19]

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the larger of two number is nine more than four times the smaller number. the sum of the two numbers is fifty-nine. find the two
VLD [36.1K]
This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y. 
We are told that X + Y = 59
 We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59    [then combine like terms]
9+5Y=59            [subtract 9 from both sides]
5Y=50                   [divide both sides by 5 to isolate the Y]
Y=10                      [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
4 0
3 years ago
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