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Airida [17]
4 years ago
14

A random sample of 157 recent donations at a certain blood bank reveals that 86 were type A blood. Does this suggest that the ac

tual percentage of type A donations differs from 40%, the percentage of the population having type A blood? Carry out a test of the appropriate hypotheses using a significance level of 0.01. State the appropriate null and alternative hypotheses.
Mathematics
1 answer:
posledela4 years ago
6 0

Answer: Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.

Step-by-step explanation:

Since we have given n = 157

x = 86

So, \hat{p}=\dfrac{x}{n}=\dfrac{86}{157}=0.55

and we have p = 0.4

So, hypothesis would be

H_0:p=\hat{p}\\\\H_a:p\neq \hat{p}

Since there is 1% level of significance.

So, test statistic value would be

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.55-0.40}{\sqrt{\dfrac{0.4\times 0.6}{157}}}\\\\z=\dfrac{0.15}{0.039}\\\\z=3.846

and the critical value at 1% level of significance , z = 2.58

Since 2.58<3.846.

So, we reject the null hypothesis.

Hence, Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.

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Dmitry [639]

Answer:

1. The equation to solve this equations is:

= 3x = 231

2. The three integers are 77, 78 and 79.

Step-by-step explanation:

The sum of 3 consecutive integers = 234

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let x+1 = second integer

let x+2 = third integer

Therefore,

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simplified to:

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b) Adding three consecutive numbers adds the smaller number to itself three times, and then adding 1 for the second number, and two for the third number. So, the sum of the three consecutive numbers is divisible by 3.  Therefore, to get the second (or middle) number, divide the total by 3, and then subtract 1 and add 2 to get the first and the third numbers, respectively.

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Answer:

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Step-by-step explanation:

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