Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
Answer:
y = 14x
Step-by-step explanation:
Use the direct variation equation, y = kx
Plug in 7 as y and 0.5 as x, and solve for k:
y = kx
7 = k(0.5)
14 = k
Plug this into the equation:
y = kx
y = 14x
So, the equation of variation is y = 14x
Answer:
B. 20x^4-39x^3+26x^2-6x
Step-by-step explanation:
(5x^2-6x+2)*(4x^2-3x)
20x^4 -15x^3 -24x^3 + 18 x^2 +8x^2 - 6x
20x^4 -39x^3 + 26x^2 - 6x
Answer:
<h2>36b + 60c</h2>
Step-by-step explanation:
Put a = 6 to the expression 2a(3b + 5c):
(2)(6)(3b + 5c) = 12(3b + 5c) <em>use the distributive property</em>
= (12)(3b) + (12)(5c) = 36b + 60c
Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500
