Answer:
The volume of the irregular figure would be 144 
.
Step-by-step explanation:
If you wish to make the process of calculating the volume easier, you can picture the irregular figure as two rectangular prisms: the large one on the bottom, and the smaller one appearing to protrude from the prism below it. Using this method, you only need to find the volumes of the two rectangular prisms and add the values together to get the volume for the irregular figure. The formula used to find the volume of a rectangular prism is 
, where 
, 
, and 
, represents the length, width, and height of the rectangular prism respectively. Using the formula above, the volume of the larger rectangular prism would be 12 * 3 * 3 = 12 * 9 = 108 , and the volume of the smaller rectangular prism would be 4 * 3 * 3 = 12 * 3 = 36 . So the volume of the entire irregular figure would be 108 + 36 = 144 .
Answer: The answer is converges r=1/7
The last choice is the right answer. Curves do not have a constant rate of change.
we have
----> inequality A
The solution of the inequality A is the interval ------> [-1,∞)
-------> inequality B
The solution of the inequality B is the interval ------> (-∞,7]
The solution of the compound inequality is
[-1,∞) ∩ (-∞,7]=[-1,7]
therefore
the answer in the attached figure
Answer:
The interval [32.6 cm, 45.8 cm]
Step-by-step explanation:
According with the <em>68–95–99.7 rule for the Normal distribution:</em> If 
is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval
![\large [\bar x - s, \bar x +s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-%20s%2C%20%5Cbar%20x%20%2Bs%5D)
around 95% of the data must fall in the interval
![\large [\bar x -2s, \bar x +2s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-2s%2C%20%5Cbar%20x%20%2B2s%5D)
around 99.7% of the data must fall in the interval
![\large [\bar x -3s, \bar x +3s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-3s%2C%20%5Cbar%20x%20%2B3s%5D)
So, the range of lengths that covers almost all the data (99.7%) is the interval
[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]
<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>
