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2 answers:
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It may help to draw a picture as you start planning this problem and draw a circle, showing a circle which represents the scale needle's range of motion 360 degrees around. The needle length will then be the radius of that circle.
We know that the needle rotated 68 degrees and are trying to find the distance it traveled in cm. To find out how far the needle traveled, we need to find the arc length - in this case, the distance between the needle's starting point and where it ended up after the oranges were placed on the scale on the circle.
There is a formula you can easily use to find the arc length
arc length = 2*
*r ( 
)
We need to input the radius, r into this formula, as well as the central angle measure c, which in this case is 68 degrees.
2(16) ( 
)
If you multiply the above formula components all together using a calculator, you will get ~18.99. (When rounded to the second decimal place.)
So, the answer is around 19 cm. (Your answer may vary depending on how your teacher usually wants you to round answers.)
We know that the needle rotated 68 degrees and are trying to find the distance it traveled in cm. To find out how far the needle traveled, we need to find the arc length - in this case, the distance between the needle's starting point and where it ended up after the oranges were placed on the scale on the circle.
There is a formula you can easily use to find the arc length
arc length = 2*
We need to input the radius, r into this formula, as well as the central angle measure c, which in this case is 68 degrees.
2
If you multiply the above formula components all together using a calculator, you will get ~18.99. (When rounded to the second decimal place.)
So, the answer is around 19 cm. (Your answer may vary depending on how your teacher usually wants you to round answers.)
Answer:
See explanation
Step-by-step explanation:
The question is incomplete because the image is missing. However, I have attached an image from Lumen learning to help you understand how to calculate the difference between two points on a straight line graph.
Given two points (x1,y1) and (x2,y2) on a straight line graph as shown in the image attached, a straight line drawn to join the two points gives the distance between the two points. This line drawn to join the points becomes the hypotenuse of a triangle ABC.
Given that;
(x2-x1) =a
(y2-y1)=b
distance =c
Recall that Pythagoras's theorem states that;
Then, according to Pythagoras's theorem;
c =√(x2-x1)2 + (y2-y1)2)
Simply put;
c=√(difference between abscissae)2 - (difference between ordinates)2
You can now substitute values and obtain a numerical result.
