Answer:
i think i know
Step-by-step explanation:
For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...
308/14 = x/1
Cross multiply
14x = 308
x = 308/14
x = 22
So the fuel efficiency is
22 miles per 1 gallon or
22/1
For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...
288 miles ÷ 48 mph =
6 hours
A^2-5a = 6
a^2-5a-6 = 0
Discriminant = (-5)^2-4(1)(-6) = 49
Discriminant is positive so there are two solutions
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