A theater group made appearances in two cities. The hotel charge before tax in the second city was $1500 higher than in the firs t. The tax in the first city was 4% , and the tax in the second city was 3.5% . The total hotel tax paid for the two cities was $408.75. How much was the hotel charge in each city before tax?
2 answers:
Answer:
Step-by-step explanation:
<u>Given</u>
Hotel charge in city 1 = x Hotel charge in city 2 = y <u>The equation for the hotel charge:</u>
<u>Taxes</u>
Tax in the city 1 = 4% = 0.04x Tax in the city 2 = 3.5% = 0.035y Total tax = $408.75 <u>The equation for the tax:</u>
<u>Substitute y and solve for x:</u>
0.04x + 0.035(x + 1500) = 408.75 0.04x + 0.035x + 52.5 = 408.75 0.075x = 408.75 - 52.5 0.075x = 356.25 x = 356.25/0.075 x = 4750 <u>Find the value of y:</u>
<u>The hotel charge was:</u>
The first city: $4750 The second city: $6250
Sorry for the delay!
Let x = charge before tax in 1st city, and y = charge before tax in 2nd city
y = $1500 + x
4/100x => tax in first city
3.5/100y => tax in second city
0.04x + 0.035y = $408.75
We have the following system of equations to solve:
So the hotel charge before tax in city 1 = $4750, and the hotel charge before tax in city 2 = $6250
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