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mel-nik [20]
2 years ago
7

10/15 as a % to 2 decimal places

Mathematics
1 answer:
PolarNik [594]2 years ago
3 0

Answer:

0.67

Step-by-step explanation:

all you need to do is divide 10 by 15

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Lemur [1.5K]
7+ 30 or 31 or 28 or 29 not sure that's what ur asking for
5 0
2 years ago
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
PLEASE HELP WILL MARK AS BRAINIEST!!!!!!!!!!
Airida [17]

Group up the like terms and combine them

2x^2 and -7x^2 add up to -5x^2

6x and 2x add up to 8x

1 and -3 add up to -2

We end up with -5x^2 + 8x - 2

<h3>Answer: Choice B</h3>
7 0
2 years ago
Read 2 more answers
How Do I solve this
stiv31 [10]

Answer:

add and multiply

Step-by-step explanation:

add them up and get your answer

then multiply that answer by 5

6 0
3 years ago
123% of what is 111?<br><br> this is one of the reasons I hate math
Olegator [25]

Answer:

90.244

Step-by-step explanation:

111 ÷ 1.23 = 90.244

6 0
3 years ago
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