Mikey bought 4 of the 500 raffle tickets sold to

1. A game is set up as follows: All the diamonds are removed from a deck of cards, and these 13 cards are placed in a bag. The c

Maurinko [17]

Answer:

the game must be played in groups of 13 draws, with a cost of $28 for the 13 draws.

Step-by-step explanation:

Probability of drawing any of the 13 balls is the same. So the expected value of play is the average of the values of each card.

The only losing card is the ace; the player loses $20 if that card is drawn.

Each of the 3 face cards wins $10; each of the remaining 9 cards wins $2.

So the average value of each draw is

$\frac{-20+3\times10+9\times2}{13}$

= 28/13

Therefore, on average the player will win $ 28/13. to be a fair game the player must pay $28/13 for a game.

that is not possible, unless the game must be played in groups of 13 draws, with a cost of $28 for the 13 draws.

7 0

3 years ago

If you are framing a photo that is 4in by 7 in, and you want the frame to be the same width all around, and the total area of th

aliina [53]

Answer:

3.36in

Step-by-step explanation:

The total surface area of the cardboard is expressed as;

TSA = 2(LW + LH + WH)

L is the length = 4in

W is the width

H is the height = 7in

TSA = 130in²

Substitute the given values into the formula and get the width W

TSA = 2(LW + LH + WH)

130 = 2(4W+4(7) + 7W)

130 = 2(11W+28)

130 = 22W+56

22W = 130 - 56

22S = 74

W = 74/22

W = 3.36in

hence the width of the photo is 3.36in

4 0

2 years ago

Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra s

algol [13]

f(x, y) = x ² - 4xy + 5

has critical points where both partial derivatives vanish:

∂f/∂x = 2x - 4y = 0 ==> x = 2y

∂f/∂y = -4x = 0 ==> x = 0 ==> y = 0

The origin does not lie in the region R, so we can ignore this point.

Now check the boundaries:

• x = 1 ==> f (1, y) = 6 - 4y

Then

max{f (1, y) | 0 ≤ y ≤ 2} = 6 when y = 0

max{f (1, y) | 0 ≤ y ≤ 2} = -2 when y = 2

• x = 4 ==> f (4, y) = 12 - 16y

Then

max{f (4, y) | 0 ≤ y ≤ 2} = 12 when y = 0

max{f (4, y) | 0 ≤ y ≤ 2} = -4 when y = 2

• y = 0 ==> f (x, 0) = x ² + 5

Then

max{f (x, 0) | 1 ≤ x ≤ 4} = 21 when x = 4

min{f (x, 0) | 1 ≤ x ≤ 4} = 6 when x = 1

• y = 2 ==> f (x, 2) = x ² - 8x + 5 = (x - 4)² - 11

Then

max{f (x, 2) | 1 ≤ x ≤ 4} = -2 when x = 1

min{f (x, 2) | 1 ≤ x ≤ 4} = -11 when x = 4

So to summarize, we found

max{f(x, y) | 1 ≤ x ≤ 4, 0 ≤ y ≤ 2} = 21 at (x, y) = (4, 0)

min{f(x, y) | 1 ≤ x ≤ 4, 0 ≤ y ≤ 2} = -11 at (x, y) = (4, 2)

5 0

3 years ago

I need help with these please! Answers please!?

timama [110]

Answer:

navada 110,567 mi²

oklahoma 69,899 mi²

Step-by-step explanation:

7 0

2 years ago

Oh and alsoo can someone plzzzzz add an explanation

Pani-rosa [81]

Answer:

Brian sold 35 tickets

Step-by-step explanation:

42/6 = 7

7 x 5 = 35

35/42 = 5/6

Brian sold 35 tickets

(I know this isn't part of the question, but Brain didn't sell 7 tickets)

5 0

2 years ago