I need help answering this question!! Why does the equation (x-4)^2 – 28 = 8 have two solutions?

Mathematics

1 answer:

andre [41]2 years ago

5 0

Answer:

For your first answer it is because they are two different ways to solve the equation

Step-by-step explanation:

For Example!

<h2>Solution 1:</h2>

(x-4)² – 28 = 8

The 8 is positive making it a different equation (this is like absolute value). (I am assuming you know the answer to the probelm)

<h2>Solution 2:</h2>

(x-4)² – 28 = -8

The 8 could be negative meaning that when you add the 28 to the right side it is -8+28 which will be a negative!

<h3>I hope this helps</h3><h2>IF IT DOES HELP PLEASE GIVE IT A BRAINLIEST!</h2>

You might be interested in

Number d I need help with

Natasha2012 [34]

Answer:

15 5/9 °C

Step-by-step explanation:

Put 60 where F is in the equation and do the arithmetic.

... C = (5/9)(60 -32) = (5/9)(28) = 140/9

... C = (135 +5)/9 = 15 5/9

8 0

3 years ago

Y varies directly as x when x= 3 and y =12 find y when x =12

andrew-mc [135]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we know that }
\begin{cases}
x=3\\
y=12
\end{cases}\implies 12=k3\implies \cfrac{12}{3}=k\implies 4=k
\\\\\\
thus\qquad \boxed{y=4x}
\\\\\\
\textit{when x = 12, what is \underline{y}?}\qquad \qquad y=4(12)$