Answer:
X= -2
Step-by-step explanation:
It takes 250 g of pasta and 240 ml of sauce to make one batch of spaghetti and it takes 600g of pasta and 700ml of sauce to make one batch of lasagna.
Case 1: Pasta
The chef wants to make spaghetti and lasagna using more than 4000 g of pasta.
S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.
So the equation becomes :
Case 2: Sauce
chef wants to make spaghetti and lasagna using more than 5000 ml of sauce.
S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.
So the equation becomes:
Answer :
The two equations are :
For pasta:
For sauce:
Answer:
q=-3 2/5
Step-by-step explanation:
First multiply -13 with (q+4)
-13q-52=7q+16
Now you have to change the order before = the numbers with q and after = the numbers without anything
-13q-7q=52+16
Remember that when you change positions the symbol too
Then solve it
-20q=68
Now u have to divide as i do
q=68/-20
you can simplify it
q=3 8/-20
Now divide by the greater divisor in this case is 4
q=3 2/-5
And organize it
q=-3 2/5
Never forget to do q=(answer)
Hopefully it helps.
9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
__
a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
__
b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
__
c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
__
d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
