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statuscvo [17]
3 years ago
11

Solve each inequality. Graph the solution on a number line.

Mathematics
1 answer:
Kamila [148]3 years ago
6 0

Step-by-step explanation:

<u>Step 1:  Find the solution for the first one</u>

4x > -36

4x / 4 > -36 / 4

x > -9 ← Solution

<u>Step 2:  Find the solution for the second one</u>

<u />7u\le-49

7y/7\le-49/7

y \le -7 ← Solution

<u>Step 3:  Find the solution for the third one</u>

-5m \ge 15

-5m / -5 \ge 15 / -5

m \le -3 ← Solution

<u>Step 4:  Find the solution for the fourth one</u>

-2p > -3

-2p / -2 > -3 / -2

p < 1.5 ← Solution

<u>Step 5:  Find the solution for the fifth one</u>

45 \le - 10r

45 / -10 \le -10r / -10

-4.5 \ge r ← Solution

<u>Step 6:  Find the solution for the sixth one</u>

<u />-66 \ge -11t

-66 / -11 \ge -11t / -11

6 \le t ← Solution

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Answer:

10.3m

Step-by-step explanation:

area of a rectangle is width times length, so you have to rearrange the equation

55.929 ÷ 5.43 = 10.3

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Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A sandwich costs $2, and hot
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A. Solution set is in the attachment (dark green shading in the middle)

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3 years ago
Select ALL the correct answers.
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Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

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Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

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Step-by-step explanation:

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The average speed of greyhound dogs is about 18.4 meters per second. A particular greyhound breeder claims that her dogs are fas
irinina [24]

Answer:

The calculated value    Z = 1.183 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

A particular greyhound breeder claims that her dogs are faster than the average greyhound

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the average speed of greyhound dogs is about 18.4 meters per second.

Size of the sample 'n' = 35

mean of the sample x⁻ = 18.7

Population standard deviation = 1.5m/s

level of significance (∝)  = 0.05

<u><em>Step(ii):-</em></u>

Null hypothesis : H₀ : μ = 18.4

Alternative  hypothesis H₁ :  μ ≠ 18.4

Test statistic

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<u><em>Conclusion:</em></u>-

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Null hypothesis is accepted

A particular greyhound breeder claims that her dogs are faster than the average greyhound

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