Answer:
Given : JKLM is a rectangle.
Prove: JL ≅ MK
Since, by the definition of rectangle all angles of rectangles are right angle.
Thus, In rectangle JKLM,
∠ JML and ∠KLM are right angles.
⇒ ∠ JML ≅ ∠KLM
Since, JM ≅ KL (Opposite sides of rectangles are congruent)
ML ≅ ML ( Reflexive )
Thus, By SAS congruence postulate,
Δ JML ≅ Δ KLM
⇒ JL ≅ MK ( because corresponding parts of congruent triangles are congruent)
Hence proved.
Answer:
whatever the answer is A cause i did my calculations and i got A
The first one is -5,-3 ab.
Answer:
The midpoint is (3, 3).
Step-by-step explanation:
We are given the two points A(9, 11) and B(-3, -5).
The midpoint is given by:

So:

The midpoint is (3, 3).
We want to show that AM = MB.
We can use the distance formula:

The distance between A(9, 11) and M(3, 3) will then be:

And the distance between B(-3, -5) and M(3, 3) will be:

So, AM = MB = 10.
Since AM = MB = 10, AM + MB = 10 + 10 = 20.
So, we want to prove that AB = 20.
By the distance formula:
