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3 years ago

15

Can someone pls help

2 answers:

Mariana [72]3 years ago

8 0

Search the answer online

evablogger [386]3 years ago

3 0

Answer:

I think B

Step-by-step:

i dont rlly like maths

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If 2 = 6, 3 =12, 4 = 20, 5 = 30, 6 = 42 then 9 = ?

Soloha48 [4]

At first you may get confused but look at those numbers carefully :)

as you see first result is divisible buy one of the product (second product in all cases is unknown)
so let's check where it will lead us :)

$6/2=3$

$12/3=4$

$20/4=5$

$30/5=6$

$42/6=7$

Now you can clearly see that every number was multiplied by number 1 higher than itself.
$2*(2+1)=6$

$3*(3+1)=12$

$4*(4+1)=20$

etc...

it means that after equation sign there should be $90$ because

$9*(9+1)=90$ :)

6 0

3 years ago

One of the tents you look at has a base measuring 3 metres long and 250 centimetres wide what is the area of the tent

ozzi

3 +250= 253 take 253 dived it by 3 ,subtract 4 =80.3

5 0

3 years ago

Given a sequence is defined by the explicit definition LaTeX: t_n=\:n^2+nt n = n 2 + n, find the 4th term of the sequence. (ie L

Harrizon [31]

Answer:

C. 20

Step-by-step explanation:

I took the Quiz and somehow my wild guess was correct lol. Hope this helps

5 0

3 years ago

Read 2 more answers

Find the point-slope equation for

iris [78.8K]

Answer: y+9=-2(x-9)

Step-by-step explanation:

The point-slope equation is $y-y_{1} =m(x-x_{1} )$ . All we have to do is fill in all the values except for y and x.

To find m, you use $\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$ . Since we are given 2 points, we cna plug them in.

$\frac{13-(-9)}{-2-9} =\frac{22}{-11} =-2$ . Now that we have our slope m, we can fill in the point slope equation.

$y-(-9)=-2(x-9)$

$y+9=-2(x-9)$

4 0

4 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Tasya [4]

$\displaystyle y = Atan(Bx - C) + D$

According to this <em>trigonometric function</em>, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{π}{6}}{1} = -\frac{π}{6} \\ Period → \frac{π}{1} = π$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{π}{B} \\ Amplitude → |A|$

NOTE: Sometimes, your <em>vertical shift</em> might tell you to extend the troughs on each end of your graphs, beyond the <em>midline</em>.

* All tangent functions have NO AMPLITUDE.

I am joyous to assist you anytime.

8 0

3 years ago