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suter [353]
3 years ago
5

Solve. –4t ≤ 48 A. t ≥ –12 B. t ≤ –12 C. t ≥ 12 D. t ≤ 12

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0
-4t \leq 48 \ \ \ : |(-4) \\  \\ t  \geq 12

<em>\\\ Ben</em>
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Which of the following coordinates is a solution to the linear equation?
Dima020 [189]
Right this is pretty simple all you do is sub the points to the equation given.
So first try the first point (2,-1) in y=-3x+7
==> -1=-3(2)+7
==>-1=1 this is not equal therefore not the right points

Then try (1,10)
==>10=-3(1)+7
==>10=4 this is incorrect therefore not the right points

Next try (3,-2)
==>-2=-3(3)+7
==>-2=-2 this is equal therefore this is the coordinates to the linear equation.

Finally try the last points to make sure you are correct.
==> -8=-3(-5)+7
==>-8=22 this is incorrect also.

Therefore the only coordinates that satisfies the equation is (3,-2)
7 0
3 years ago
I need help ASAP please
trapecia [35]

Answer:

B

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = \frac{1}{\sqrt{2} } , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{3}{c} = \frac{1}{\sqrt{2} } ( cross- multiply )

c = 3\sqrt{2}

5 0
2 years ago
Homer wants to identify the center and radius of the circle defined by the equation...​
Goryan [66]

Answer:

Step 2, he didn't add the values he completed the square with to both sides.

Step-by-step explanation:

When you complete the square, you need to add the values to both sides, not just one.

So when Homer added 49 + 1 or 50 to the left side of the equation, he should've also added 50 to the right side of the equation.

Hence, the equation would now be :

(x-7)^2 + (y+1)^2 = 75

8 0
3 years ago
Select whether each system of equations has no solution, one solution, or infinitely many solutions.
Firdavs [7]
I’m not sure!!!!!!!!!!!!!!!!!!
8 0
2 years ago
Please help !!!!!!!!!! Will mark Brianliest answer !!!!!!!
ivanzaharov [21]
The answer is most likely (c).
3 0
2 years ago
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