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3 years ago

Keenan buys an embroidery machine for $1,400. He uses it to embroider

Mathematics

1 answer:

kvv77 [185]3 years ago

6 0

Answer:

the graph shift down 135 units

Step-by-step explanation:

when there is no fixing cost:

f(x)=12x-1400

when there is fixing cost (0ne time): 12x-(1400+135)

the graph shift down 135 units

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Question 30

V125BC [204]

Answer:

a. 26 ft

Step-by-step explanation:

When triangles are similar their sides are proportional

4/8 = h/(44+8)

1/2(52) = h

h = 26

6 0

3 years ago

Evalute 27⋅((3^3)^−1)

shtirl [24]

Answer: 0.81

Step-by-step explanation:

=27⋅((3^3)^−1)

Do the brackets first:

3^3 is the same as 3³ so it is 27

then:

27^-1 equals 0.03

And lastly:

multiply 27 and 0.03

27(0.03)=0.81

8 0

3 years ago

Can you help me plsssssssss

denpristay [2]

Answer:

im 70% sure that its D

Step-by-step explanation:

I hope i helped sorry if im wrong :D

3 0

2 years ago

Read 2 more answers

Change the following decimals to fractions: 45

ELEN [110]

Answer:

45÷100

=0.045 is your answer

3 0

2 years ago

Which of the following shows that EFGH is a parallelogram for y=7 and z=9?

Anna35 [415]

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Explanation:

Option A: $m \angle E=m \angle F=60^{\circ}$ and $m \angle G=120^{\circ}$ so $\angle G$ is supplementary to both $\angle E$ and $\angle F$ , so EFGH is a parallelogram

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we get, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Thus, $m \angle E\neq m \angle F$ because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Hence, Option B is the correct answer.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

To determine the angles, let us substitute $z=9$ in $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$

Thus, $m \angle F=m \angle G=120^{\circ}$

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Adding the angles E and G, we have,

$m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}$

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

3 0

3 years ago