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3 years ago

Keenan buys an embroidery machine for $1,400. He uses it to embroider

Mathematics

1 answer:

kvv77 [185]3 years ago

6 0

Answer:

the graph shift down 135 units

Step-by-step explanation:

when there is no fixing cost:

f(x)=12x-1400

when there is fixing cost (0ne time): 12x-(1400+135)

the graph shift down 135 units

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A store sells a package of comic books with a poster. A poster and three comic books cost $10.50. A poster and 12 comics cost $1

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3 years ago

Okay, here's the last four questions i need help with :)

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2 years ago

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Guys!!! I need help ASAP!!!!

loris [4]

<h2><u>Solution 1</u> :</h2>

Cost of $1\frac{1}{3}$ pounds of gummy bears = $4.40

Cost of 1 pound of gummy bears :

$= 4.40 \div 1 \frac{1}{3}$

$= \frac{440}{100} \div \frac{4}{3}$

$= \frac{440}{100} \times \frac{3}{4}$

$= \frac{1320}{400}$

$= \frac{1320 \div 20}{400 \div 20}$

$= \frac{66}{20}$

$= \frac{66 \div 2}{20 \div 2}$

$= \frac{33}{ 10 }$

$= 3 \frac{3}{10}$

$= \color{plum}\bold{\$3.3}$

Therefore, 1 pound of gummy bears = <u>$3.3</u>

<h2><u>Solution 2</u> : </h2>

Cost of 1 pound of gummy bears = $3.3

Money Daniel has = $1.00

Quantity of gummy bears he can afford :

$= 1 \div 3.3$

$= 1 \div 3 \frac{3}{10}$

$= 1 \div \frac{33}{10}$

$= 1 \times \frac{10}{33}$

$= \frac{10}{33}$

$= 0.30$

Therefore, Daniel will be able to buy <u>0.30 pounds</u> of gummy bears from Jio.

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2 years ago