The distance between (x1, y1) and (x2, y2) is found using the Pythagorean theorem. It is ...
For your values of (x1, y1) = (6, 5) and d = 5, substituting into the formula gives
This matches the first selection.
Answer:
https://www.bartleby.com/solution-answer/chapter-91-problem-80es-mathematical-excursions-mindtap-course-list-4th-edition/9781305965584/solve-the-formula-for-the-indicated-variable-ana1n1dd-mathematics/b6652e41-6bcd-11e9-8385-02ee952b546e
Step-by-step explanation:
Answer:
a.2^(a+b+c)
b.2^(a+b+a-b)=2^(2a)or 4^a
c.2^(a+b+c)/2^(a+b)=2^(a+b+c-a-b)=2^c
Answer:
b/a = 3
Step-by-step explanation:
f(x) / (x²-4x-12) = Q(x) + (x+6)/(x²-4x-12)
f(x) = Q(x)*(x²-4x-12) + (x+6)
x= - 2 ... when f(x) is f(-2) x²-4x-12 = 4+8-12 = 0
a = f(-2) = Q(x)*0 + (-2 + 6) = 4
x= 6 ... when f(x) is f(6) x²-4x-12 = 36-24-12 = 0
b = f(6) = Q(x)*0 + (6 + 6) = 12
b/a = 12/4 = 3
H = m/y + z/y - d
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