1. area of a pentagon when 1 side is x is
![\frac{x^2}{4}\sqrt{5(5+2\sqrt{5})}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B4%7D%5Csqrt%7B5%285%2B2%5Csqrt%7B5%7D%29%7D)
so if perimiter is 100 then one side is 100/5 or 20
area will be
![\frac{20^2}{4}\sqrt{5(5+2\sqrt{5})}](https://tex.z-dn.net/?f=%5Cfrac%7B20%5E2%7D%7B4%7D%5Csqrt%7B5%285%2B2%5Csqrt%7B5%7D%29%7D)
≈<span>688.2 square yards
2. area of a hexagon when 1 side is length x is
![\frac{3x^2\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E2%5Csqrt%7B3%7D%7D%7B2%7D)
so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be
![\frac{3(16.6666666)^2\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%2816.6666666%29%5E2%5Csqrt%7B3%7D%7D%7B2%7D)
≈721.7 square yards
3. area of a regular octagon with side lenghts x is
![2(1+\sqrt{2})x^2](https://tex.z-dn.net/?f=2%281%2B%5Csqrt%7B2%7D%29x%5E2)
so if 8 sides then side length of each is 100/8 or 12.5
area will be
![2(1+\sqrt{2})12.5^2](https://tex.z-dn.net/?f=2%281%2B%5Csqrt%7B2%7D%2912.5%5E2)
≈754.4 square yards
octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter
</span>
15 goes into 18 once with 3 remainder.
18/15-15/15=3/15=1/5
So the answer is:
Answer:
The answer is definitely Option A
1. Fermentation. 2. they would die as they wouldn't get energy. 3. short run because frementation occurs only when we r tired and we will be tired as we run it can be either long or short run.
i hope u understand plz inform me