The inclination to the nearest tenth of a degree exists 0.24146
<h3>What is the inclination to the nearest tenth of a degree?</h3>
The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.
Given: H = 4.6 m and P = 1.1 m
We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse
Let x be the angle then
sin x = P/H
sin x = 1.1/4.6
sin x = 0.23913
= 0.24146
The inclination to the nearest tenth of a degree exists 0.24146
To learn more about trigonometric ratios refer to:
brainly.com/question/14033725
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Use the formula of arc length that is
s = rθ
where s = arc length, r = radius, θ = angle (unit must be in radian)
Given r = 5 in and θ = 48°( π /180°) = (4/15)* π = 0.2667 π,
s = 5 in (0.2667π) = 1.333 π in
104/ 8 = 13.
Every hour she vacuumed 13 cars.
77 times 100 is 7,700. So your answer is 7,700