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notsponge [240]
3 years ago
14

I am thinking of a number i multiply by 11 and add 22 i get the same answer if i miltiply by 4 and add 113 whats my number

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer: 13

Step-by-step explanation:

Let the number that in thinking of be represented by x.

I multiply by 11 and add 22 will give the same answer as multiplying by 4 and adding 113. This.csn be firmed into an equation as:

(11 × x) + 22 = (4 × x) + 113

11x + 22 = 4x + 113

Collect like terms

11x - 4x = 113 - 22

7x = 91

x = 91/7

x = 13.

The number is 13

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F2× d2² = F1× d1²

F2 × 4m² = 10 N × 16 m²

F2 = (10 N × 16 m^2) / 4 m² F2

= 10 N× (16 m² /4 m²)

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The gravitational force produced when they are kept 2 meters apart is 40 N.

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soldier1979 [14.2K]

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A 10 ft ladder is being pulled away from a wall at a rate of 3 ft/sec. What is the rate of change in the area beneath the ladder
andriy [413]

Answer:

The rate of change in the area beneath the ladder is 5.25 ft²/s

Step-by-step explanation:

Area of triangle is given by;

A = \frac{1}{2}bh\\\\2A = bh\\\\take \ derivative  \ of \ both \ sides \ with \ respect  \ to \ "t"\\\\2\frac{dA}{dt} = h\frac{db}{dt} + b\frac{dh}{dt}\\\\divide \ through \ by \ 2\\\\\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}

where;

b is the base of the triangle, given as 6 ft

h is the height of the triangle, determined  by applying Pythagoras theorem.

h² = 10² - 6²

h² = 100 - 36

h² = 64

h = √64

h = 8 ft

Determine the rate of change of the height;

h^2 + b^2 = 10^2\\\\h^2 + b^2 =100\\\\2h\frac{dh}{dt} + 2b\frac{db}{dt} =0\\\\h\frac{dh}{dt} + b\frac{db}{dt} =0\\\\h \frac{dh}{dt}  = -b\frac{db}{dt} \\\\\frac{dh}{dt}  = (\frac{-b}{h} )\frac{db}{dt}\\\\\frac{dh}{dt}  =(\frac{-6}{8})(3)\\\\\frac{dh}{dt}  = -\frac{9}{4} \ ft/s

Finally, determine the rate of change of area beneath the ladder;

\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}\\\\\frac{dA}{dt} = (\frac{8}{2} )(3) + (\frac{6}{2}) (\frac{-9}{4})\\\\\frac{dA}{dt} = 12 - \frac{27}{4} \\\\\frac{dA}{dt} = \frac{48-27}{4}\\\\\frac{dA}{dt} = \frac{21}{4} \ ft^2/s\\\\\frac{dA}{dt} =  5.25 \ ft^2/s

Therefore, the rate of change in the area beneath the ladder is 5.25 ft²/s

5 0
3 years ago
What is the axis of symmetry for y=-5x^2-10x-13
sergey [27]
AOS is the x value of the vertex.
x = -b/2a
x = 10/2*-5
x = 10/-10
x = -1
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4 years ago
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