2 years ago

Please hurry it’s missing and I need it fast

Mathematics

2 answers:

sattari [20]2 years ago

3 0

2. 83 R 2
3. 82 R 1111 etc

aalyn [17]2 years ago

3 0

2) 83 with R1
3) 82 with R1

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A 20-foot cable hangs from the top of a building that is 50 feet high. if the cable weighs 2 pounds per foot, how much work is d

pychu [463]

20*2=40
40*50=2000
2000/60=33.33
about 33 hours by lifting by hand

4 0

3 years ago

Complete the explanation of the procedure that can be used to solve 5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55. Then solve the e

Debora [2.8K]

Answer:

x = 2.

Step-by-step explanation:

5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55

5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55

5[5x + 10] - x - 15 = 14x + 55

25x + 50 - x - 15 = 14x + 55 Now we subtract 14x from both sides:

25x + 50 - x - 15 - 14x = 14x - 14x + 55

10x + 50 - 15 = 55 Now we subtract 50, add 15 to both sides:

10x + 50 - 50 - 15 + 15 = 55 - 50 + 15

10x = 20

x = 2.

8 0

3 years ago

Plane A leaves eastaboga traveling east at a speed twice that of plane be which is flying west. how fast is each plane traveling

ivanzaharov [21]

Your doing great keep up the good work!!

5 0

3 years ago

Three times a number increased by ten equal to twenty less than six times a number . find the number

kiruha [24]

Answer:

the number is 10

Step-by-step explanation:

3x + 10 = 6x-20

20+10=6x-3x

30=3x

x=10

4 0

3 years ago

Read 2 more answers

Increasing numbers of businesses are offering child-care benefits for their workers. However, one union claims that fewer than 8

Y_Kistochka [10]

Answer: c. -2.15

Step-by-step explanation:

As per given we have:

Null hypothesis : $H_{a}: p\geq0.80$

Alternative hypothesis : $H_{a}: p$

let p be the proportion of firms in the manufacturing sector offer child-care benefits

A random sample of 390 manufacturing firms is selected and 295 of them offered child-care benefits.

sample size : n= 390

sample proportion : $\hat{p}=\dfrac{295}{390}=0.7564$

Test statistic for proportion :

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Substitute the values , we get

$z=\dfrac{0.7564-0.80}{\sqrt{\dfrac{0.80(1-0.80)}{ 390}}}$

$z=\dfrac{-0.0436}{\sqrt{0.000410256410256}}$

$z=-2.15257752474\approx-2.15$

Hence, the value of test statistic = -2.15

Correct option is c. -2.15 .

4 0

3 years ago