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nikklg [1K]
3 years ago
10

Factor 3pq + 6p - 5q - 10. ( q - 2)( p + 5) (3 p + 5)( q + 2) (3 p - 5)( q + 2)

Mathematics
1 answer:
ioda3 years ago
8 0

Answer:

(3p-5 )(q+2)

Step-by-step explanation:

3pq + 6p - 5q -10

3p (q+2) -5 (q+2)

(q+2) (3p-5)

That is your complete answer

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The solution for y=2x-4: y= -8

The solution for y=3x-4: y= -12
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When the weght of apples is increased by 4 what is the total cost increase
inn [45]
The answer will be is 1
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3 years ago
PLEASE HELP the formula m=12,000+12,000rt/12t gives keri's monthly loan payment where t is the annual interest rate and t is the
tatiyna

Answer:

The answer is below

Step-by-step explanation:

The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.

Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

m=\frac{12000+12000rt}{12t}\\ but\ m\leq275, \ and \ r=10\%=0.1\\275= \frac{12000+12000(0.1)t}{12t}\\275= \frac{12000}{12t} +\frac{12000(0.1)}{12t}\\275= \frac{1000}{t} + 100\\275-100= \frac{1000}{t} \\175= \frac{1000}{t} \\175t = 1000\\t= \frac{1000}{175}\\ t=5.72\ years

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%

3 0
3 years ago
To prove ABC= ADC, To prove which triangle postulate could you use?
Kay [80]

Answer:

ASA

Step-by-step explanation:

..................

6 0
3 years ago
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Abigail is 8 years older than Cynthia.Twenty years ago Abigail was three times as old as Cynthia.How old is each now?
xz_007 [3.2K]
Let 
C=Cynthia's age today
A=Abigail's age today

then
at all times
A=C+8......................(1)
twenty years ago,
A-20=3(C-20)
simplifying
A=3C-40...................(2)

Equate (1) and (2),
C+8=3C-40
8+40=3C-C
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=> 
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Check:  A-C=8... ok   A-20=12  C-20=4  => (A-20)=3(C-20) ...ok

Answer:
Abigail is 32, Cynthia is 24.
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4 years ago
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