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nikklg [1K]
3 years ago
10

Factor 3pq + 6p - 5q - 10. ( q - 2)( p + 5) (3 p + 5)( q + 2) (3 p - 5)( q + 2)

Mathematics
1 answer:
ioda3 years ago
8 0

Answer:

(3p-5 )(q+2)

Step-by-step explanation:

3pq + 6p - 5q -10

3p (q+2) -5 (q+2)

(q+2) (3p-5)

That is your complete answer

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Divide £24 in ratio 3:5
Nadya [2.5K]
When i divide into ratio, i like to think of them as units:

so 24 will be divided into units, where the first thing gets 3 units and the second 5 units. In total those are 3+5=8 units.


so each unit will have 24/8=4

so the division into the two numbers is like this: the first one gets 3 units (3*4=12) and the second 5 (5*4=20)
so it's 12:20. 


4 0
3 years ago
Which statement must be true?<br><br> a<br> b<br> c<br> d
lozanna [386]
ANSWER

\boxed {m \ne0}



EXPLANATION


The given function is

f(x) = mx + b


We need to find the inverse of this function,



Let

y= mx + b


We interchange x an y to obtain,


x = my + b


We solve for y now to obtain,


x - b = my


We divide through by m to get,

\frac{x - b}{m}  = y


Hence the inverse function is ,


{f}^{ - 1} (x) =  \frac{x - b}{m}


For this inverse to exist, the denominator must not be equal to zero,

Thus

m \ne0


The correct answer is A.
8 0
3 years ago
Read 2 more answers
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Nina [5.8K]

Answer: The answer is C, 2 screws.

8 0
2 years ago
Find the sum of the two least whole numbers such that each of the two numbers has a remainder of 1 when divided by 5 and a remai
Drupady [299]

Answer:

<u>The correct answer is B. 82</u>

Step-by-step explanation:

The numbers are 56 and 26.  Let's prove it:

56/5 = 11 and a remainder of 1

56/6= 9 and a remainder of 2

26/5 = 5  and a remainder of 1

26/6 = 4 and a remainder of 2

56 + 26 = 82

<u>The correct answer is B. 82</u>

4 0
3 years ago
A box contains $7.45 in nickels, dimes, and quarters. There are 43 coins in all, and the sum of the numbers of nickels and dimes
kari74 [83]

Answer:

<em>Number of nickels = 6</em>

<em>Number of dimes = 14</em>

<em>Number of quarters = 23</em>

<em></em>

Step-by-step explanation:

Total number of coins = 43

Let number of nickels = n

Let number of dimes = d

Let number of quarters = q

n+d+q=43 ...... (1)

Money in n nickels = n \times 0.05

Money in d dimes = d \times 0.10

Money in q quarters = q \times 0.25

Total money = $7.45

0.05n +0.10d+0.25q = 7.45\\\Rightarrow 5n +10d+25q = 745 .... (2)

The sum of the numbers of nickels and dimes is 3 less than the number of quarters.

i.e.

n+d=q-3

Let us put the value  in (1):

q-3+q=43\\\Rightarrow 2q= 43+3\\\Rightarrow q =23

Putting the value of q in (1) and (2):

n+d = 20 .... (3)

5n+10d+575 =745\\\Rightarrow 5n+10d =170\\\Rightarrow  n+2d =34 .... (4)

(4) - (3):

d = 14

Now, from (3):

n = 6

<em>Number of nickels = 6</em>

<em>Number of dimes = 14</em>

<em>Number of quarters = 23</em>

5 0
3 years ago
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