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andre [41]
2 years ago
14

The value of 0.01 gramis equivlent to

Mathematics
2 answers:
mina [271]2 years ago
8 0

Answer:

1 milligrams

milligrams

Art [367]2 years ago
5 0

Answer:

10 milligrams

Step-by-step explanation:

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As part of a research project on student debt at TWU, a researcher interviewed a sample of 35 students that were chosen at rando
Inga [223]

Answer:

Option a is right

Step-by-step explanation:

Given that as part of a research project on student debt at TWU, a researcher interviewed a sample of 35 students that were chosen at random concerning their monthly credit card balance.

Sample average = 2573

Variance = 4252

Sample size = 35

STd deviation of X = \sqrt{4252} \\=65.21

Score of student selected at random X=1700

Corresponding Z score = \frac{1700-2573}{65.201} \\=-13.38

Rounding of we get Z score = -13.4

option a is right

6 0
3 years ago
A statue casts a shadow that is 45 feet
exis [7]
It’s not my answer but I think it’s correct!

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3 years ago
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Musya8 [376]

Answer:

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Step-by-step explanation:

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2 years ago
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Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.
Digiron [165]

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

x ^ 2-1 = 0\\x ^ 2 = 1

So the roots are:

x = 1\\x = -1

Therefore we can write the expression in the following way:

x ^ 2-1 = (x-1)(x + 1)

Now the expression is as follows:

\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

x = 1\\x = -1\\x = 2

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

(x-1)\geq0 when x\geq-1

(x + 1)\geq0 when x\geq1

and

(x-2) ^ 2 is always \geq0

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

6 0
3 years ago
How can you check the reasonableness of your solution
storchak [24]

You would basically go back and trace all your steps, that's what I do. And if your answer seems reasonable then you have the right answer but if your work doesn't match the answer than you've messed up.   I hope I helped if I did like my answer and comment down below thx

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3 years ago
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