Somebody please help me

In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.

mel-nik [20]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle ABC

$\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: - - - (1) }$

$\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \: - - - (2)}$

We know,

Sum of all interior angles of a triangle is supplementary.

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }$

On adding equation (1) and (2), we get 

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree + 150 \degree \:}$

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 95\degree \:}$

On substituting the value in equation (1) and (2), we get

$\purple{\rm :\longmapsto\:\angle A + 95\degree = 125\degree }$

$\purple{\rm :\longmapsto\:\angle A = 125\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle A = 30\degree }$

Also, from equation (2), we get

$\purple{\rm :\longmapsto\:95\degree + \angle C = 150\degree }$

$\purple{\rm :\longmapsto\:\angle C = 150\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle C = 55\degree }$

Hence,

$\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree } \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}$

3 0

3 years ago

Read 2 more answers

Is 44.65 equal to 44.650

Zina [86]

Yes it is. If you see any zero after the last number after a decimal point and then compare the same numbers but without the zero they are equivalent.

4 0

3 years ago

Read 2 more answers

In triangle abc the measure of angle a = measure of angle b + 30, the measure of angle c = measure of angle b + 60. find the mea

Morgarella [4.7K]

B 60.5
a 90.5
c 120.5
follow the steps in the picture

4 0

4 years ago

-3.75+2(-4x+6.1)-3.25

Pani-rosa [81]

The value of x is 0.65

Step-by-step explanation:

This solution is given by solving the given problem using BODMAS rule.

This means that the steps to be followed to find the solution should be in the order of BODMAS rule.

B- Bracket, O- of, D- Division, M- Multiplication, A- Addition, S- Subtraction.

This rule states that the 1st operation must be done for Brackets.

⇒ -3.75+2(-4x+6.1)-3.25 = 0

⇒ -3.75 -8x + 12.2 -3.25 = 0

The addition operation should be performed next and then followed by subtraction.

⇒ -8x -7+ 12.2 = 0

To find the value of x :

Keeping the x term alone on one side and moving the constants on other side,

⇒ -8x = -12.2 + 7

⇒ -8x = -5.2

⇒ x = 5.2/8

⇒ x = 0.65

3 0

3 years ago

Calvin encoded a secret phrase using matrix multiplication. Using A = 1, B = 2, C = 3, and so on, he multiplied the clear text c

Vlad1618 [11]

Our matrix C is the encoder. Let X be our secret message and let B be our encoded message. Therefore the relationship between the 3 can be represented as:

CX = B

So we want to solve for X (our secret message). So using matrix algebra:

X = C^-1*B
where C^-1 is the inverse of C.

C^-1 = | 3 -2 |
|4 -3 |

So we take C^-1 and multiply it by matrix B to get X. Matrix B is already given to us. So just multiply those two. I used a calculator to get:

X = | 20 8 5 3 15 12 15 |
| 18 9 19 2 12 21 5 |

And since A = 1, B = 2, C = 3, etc....

We decode our message and it says:

X = | T H E C O L O |
| R I S B L U E |

So the answer is: The color is blue (D)

8 0

4 years ago