b). empty set, {–3}, {6}, {–3, 6}
Answer:
Step-by-step explanation:
one hour makes 3.75
20*3.75 = 75
<span>The equation of the linear function is given in the form of a directional
</span><span>equation consists of solid :
1.współczynniki a and b .
2. The variables x and y
</span>y= 3x - 12
y = ax + b
a = 3 (<span>the slope of the tangent to the x-axis)
</span>b = - 12 (<span>intersection of the axis y)
</span>we look for the point ( 0 , -12 ) because b = -12
A. (4, 0) ,(0, -12)
B.(12 ,0), (0,4)
C.(3, 0), (0, 4)
D.(4, 0), (0, 3)
E.(-4, 0), (0, -12)
<span>fit and answers a,e
</span>
<span>we set the coordinate system and you activate the point ( 0 , -12 )
</span><span>Now draw a straight line parallel to the x axis przchodzącą through the point (0 , -12 )
</span><span>We notice that a> 0 the function is increasing
</span><span>We draw a line parallel to the triangle . Invent lengths of the sides 3 : 1. Examples are a = b = 1cm 3cm and 6cm a = b = 2 cm .
</span><span>the hypotenuse of the triangle is our simple
</span><span>Intersection of the axis x = ( 4,0 )
Answer A</span>
Answer:
Profit = Selling price - Variable cost
Formulas:
F2 =SUMPRODUCT(B2:E2,$B$16:$E$16) copy to F2:F12, F14
Optimal solution: The company should produce the following quantities (in pounds) of the four varieties of nuts.
Whole = 1000
Cluster = 500
Crunch = 80
Roasted = 200
Total profit = $ 2913.20
Step-by-step explanation:
Answer:
$180000
Step-by-step explanation:
Let's c be the number of chair and d be the number of desks.
The constraint functions:
- Unit of wood available 4d + 3c <= 2000 or d <= 500 - 0.75c
- Number of chairs being at least twice of desks c >= 2d or d <= 0.5c
c >= 0
d >= 0
The objective function is to maximize the profit function
P (c,d) = 400d + 250c
We draw the 2 constraint functions (500 - 0.75c and 0.5c) on a c-d coordinates (witch c being the horizontal axis and d being the vertical axis) and find the intersection point 0.5c = 500 - 0.75c
1.25c = 500
c = 400 and d = 0.5c = 200 so P(400, 200) = $250*400 + $400*200 = $180,000
The 500 - 0.75c intersect with c-axis at d = 0 and c = 500 / 0.75 = 666 and P(666,0) = 666*250 = $166,500
So based on the available zones in the chart we can conclude that the maximum profit we can get is $180000