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algol [13]
3 years ago
6

What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3

Mathematics
2 answers:
elena-s [515]3 years ago
6 0
9xy2-6x2y+5x3.  Change every sign in the equation as if you were multiplying each part by -1.
kobusy [5.1K]3 years ago
6 0

Answer:  The required additive inverse of the given polynomial is 9xy^2-6x^2y+5x^3.

Step-by-step explanation:  We are given to find the additive inverse of the following polynomial :

P=-9xy^2+6x^2y-5x^3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let Q be the polynomial that represents the additive inverse of the polynomial P.

Then, the sum of the polynomials P and  must be zero.

That is,

P+Q=0\\\\\Rightarrow (-9xy^2+6x^2y-5x^3)+Q=0\\\\\Rightarrow Q=0-(-9xy^2+6x^2y-5x^3)\\\\\Rightarrow Q=0+9xy^2-6x^2y+5x^3\\\\\Rightarrow Q=9xy^2-6x^2y+5x^3.

Thus, the required additive inverse of the given polynomial is 9xy^2-6x^2y+5x^3.

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4 0
3 years ago
Find the smallest number to be added to 11650 so that the sum will be a perfect square ​
sergejj [24]

Answer:

14

Step-by-step explanation:

Take the square root of 11650+14:

%:11650+14

108

So it’s a perfect square (108^2=11664).

3 0
3 years ago
Suppose that the ingredients for a large bucket of popcorn cost a movie theater 80 cents
Marat540 [252]

Answer:

The percent markup is 91%.

Step-by-step explanation:

1. find the amount of profit per large bucket of popcorn

9 - 0.8 = $8.2

2. divide the amount of profit per large bucket of popcorn by the cost of a large bucket of popcorn

8.2 / 9 = <u>91%</u>

3 0
3 years ago
Read 2 more answers
A trough is 8 feet long and has perpendicular cross section in the shape of an isosceles triangle (point down) with base 1 foot
murzikaleks [220]

Answer:

Dh/dt  = 0.082 ft/min

Step-by-step explanation:

As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of  1 feet and height     h = 2 feet.

The volume of a circular cone is:

V(c)  = 1/3 * π*r²*h

Then differentiating on both sides of the equation we get:

DV(c)/dt   = 1/3* π*r² * Dh/dt   (1)

We know that DV(c) / dt   is  1 ft³ / 5 min      or     1/5  ft³/min

and  we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment

By proportion we know

r/h  ( at the top of the cone  0,5/ 2)   is equal to  r/0.5  when water is 1/2 foot deep

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r  =  (0,5)*( 0.5) / 2        ⇒   r  =  0,125 ft

Then in equation (1) we got

(1/5) / 1/3* π*r² =  Dh/dt

Dh/dt  = 1/ 5*0.01635

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4 0
3 years ago
Cuanto es la raíz cubica de 27
zlopas [31]

Answer:

3

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Step-by-step explanation:


6 0
3 years ago
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