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algol [13]
3 years ago
6

What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3

Mathematics
2 answers:
elena-s [515]3 years ago
6 0
9xy2-6x2y+5x3.  Change every sign in the equation as if you were multiplying each part by -1.
kobusy [5.1K]3 years ago
6 0

Answer:  The required additive inverse of the given polynomial is 9xy^2-6x^2y+5x^3.

Step-by-step explanation:  We are given to find the additive inverse of the following polynomial :

P=-9xy^2+6x^2y-5x^3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let Q be the polynomial that represents the additive inverse of the polynomial P.

Then, the sum of the polynomials P and  must be zero.

That is,

P+Q=0\\\\\Rightarrow (-9xy^2+6x^2y-5x^3)+Q=0\\\\\Rightarrow Q=0-(-9xy^2+6x^2y-5x^3)\\\\\Rightarrow Q=0+9xy^2-6x^2y+5x^3\\\\\Rightarrow Q=9xy^2-6x^2y+5x^3.

Thus, the required additive inverse of the given polynomial is 9xy^2-6x^2y+5x^3.

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Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av
s344n2d4d5 [400]

Nikita's distance from her for the second part of the race was 1.5 kilometers.

Since Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand, and in the first part of the race, her average speed was 8.75 kilometers per hour, while for the second part of the race, she started to get tired, so her average speed dropped to 6 kilometers per hour, to determine which expression represents Nikita's distance for the second part of the race the following calculation must be performed:

  • 8.75 x 0.65 + 6 x 0 = 5.68
  • 8.75 x 0.50 + 6 x 0.15 = 5.275
  • 8.75 x 0.40 + 6 x 0.25 = 5
  • 100 = 60
  • 40 = X
  • 40 x 60/100 = X
  • 24 = X
  • 39 - 24 = 15
  • 15 = 1/4 hour
  • 6/4 = 1.5

Therefore, Nikita's distance from her for the second part of the race was 1.5 kilometers.

Learn more about maths in brainly.com/question/22791791

6 0
2 years ago
4,12,20, 28 nth term
Anna007 [38]

Answer:

8n - 4

Step-by-step explanation:

The numbers here go up in 8, so you have 8n. Afterwards, use the term and the 8 times tables. Eg. 4 is the first term and the first 8 multiple is 8, so 4-8. You have to subtract 4 from 8 to get the first term. Sorry if this didn't help but yeah...

3 0
2 years ago
I am the distance around the circle- it's perimeter WHAT AM I?​
mart [117]
I believe the answer is the circumference
8 0
2 years ago
Solve the equation |x-2|-3=0 first by finding the zeros of<br> y=|x-2|-3 and then algebraically.
tino4ka555 [31]

Answer:

The solution of given equation are -1 and 5.

Step-by-step explanation:

The given equation is

|x-2|-3=0

We need to solve the above equation by finding the zeros of

y=|x-2|-3

The vertex form of an absolute function is

y=a|x-h|+k

where, a is constant and (h,k) is vertex.

Here, h=2, k=-3. So vertex of the function is (2,-3).

The table of values is

   x           y

   0         -1

   2         -3

   4         -1

Plot these points on a coordinate plane and draw a V-shaped curve with vertex at (2,-3).

From the given graph it is clear that the graph intersect x-axis at -1 and 5. So, zeroes of the function y=|x-2|-3 are -1 and 5.

Therefore the solution of given equation are -1 and 5.

Now solve the given equation algebraically.

|x-2|-3=0

Add 3 on both sides.

|x-2|=3

x-2=\pm 3

Add 2 on both sides.

x=\pm 3+2

x=3+2 and x=-3+2

x=5 and x=-1

Therefore the solution of given equation are -1 and 5.

3 0
3 years ago
Suppose the line segment whose endpoints are H(5,0) and I(-6,-3) is reflected over the x-axis? What are the coordinates H’I’?
Brrunno [24]
The y coordinates would become the opposite/ H': (5,0) I': (-6,3)
3 0
2 years ago
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