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docker41 [41]
3 years ago
14

(with solution)

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and c the y- intercept )

(1)

Here m = 6 and b = - 2, then

y = 6x - 2

(2)

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Here m = - 2 and b = 5, then

y = - 2x + 5 ← equation in slope- intercept form

Add 2x to both sides

2x + y = 5 ← equation in standard form

(3)

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (6, - 13) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+13}{-4-6} = \frac{10}{-10} = - 1 , then

y = - x + b ← is the partial equation

To find b substitute either of the 2 points into the partial equation

Using (- 4, - 3 ) , then

- 3 = 4 + b ⇒ b = - 3 - 4 = - 7

y = - x - 7 ← equation in slope- intercept form

Add x to both sides

x + y = - 7 ← equation in standard form

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For what real value of $v$ is $\frac{-21-\sqrt{301}}{10}$ a root of $5x^2+21x+v$?
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Answer:

v = 7

is the value for which

x = (-21 - √301)/10

is a solution to the quadratic equation

5x² + 21x + v = 0

Step-by-step explanation:

Given that

x = (-21 - √301)/10 .....................(1)

is a root of the quadratic equation

5x² + 21x + v = 0 ........................(2)

We want to find the value of v foe which the equation is true.

Consider the quadratic formula

x = [-b ± √(b² - 4av)]/2a ..................(3)

Comparing (3) with (2), notice that

b = 21

2a = 10

=> a = 10/2 = 5

and

b² - 4av = 301

=> 21² - 4(5)v = 301

-20v = 301 - 441

-20v = -140

v = -140/(-20)

v = 7

That is a = 5, b = 21, and v = 7

The equation is then

5x² + 21x + 7 = 0

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