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docker41 [41]
3 years ago
14

(with solution)

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and c the y- intercept )

(1)

Here m = 6 and b = - 2, then

y = 6x - 2

(2)

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Here m = - 2 and b = 5, then

y = - 2x + 5 ← equation in slope- intercept form

Add 2x to both sides

2x + y = 5 ← equation in standard form

(3)

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (6, - 13) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+13}{-4-6} = \frac{10}{-10} = - 1 , then

y = - x + b ← is the partial equation

To find b substitute either of the 2 points into the partial equation

Using (- 4, - 3 ) , then

- 3 = 4 + b ⇒ b = - 3 - 4 = - 7

y = - x - 7 ← equation in slope- intercept form

Add x to both sides

x + y = - 7 ← equation in standard form

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4 years ago
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Is this question correct?
Andrews [41]

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6 0
3 years ago
What are the real solutions of x squared =225
Gnesinka [82]

The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

x² = 225

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Therefore, the real solutions of the equation are; +25 and -25.

Read more on real solutions of equations;

brainly.com/question/3122484

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