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Paha777 [63]
2 years ago
14

4. Here are the equations that define three functions.

Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

The functions f(x), g(x) and h(x) are all linear functions

  • The function value that is largest is h(-100)
  • The function value that is largest is h(-100)
  • The function value that is largest is f(1/100)

<h3>How to determine the function with the largest values</h3>

The functions are given as:

f(x) = 4x - 5

g(x) = 4(x - 5)

h(x) = x/4 -5

At x = 100, we have:

f(100) = 4 * 100 - 5 = 395

g(100) = 4 * (100 - 5) = 380

h(100) = 100/4 - 5 = 20

Hence, the function value that is largest is f(100)

At x = -100, we have:

f(-100) = -4 * 100 - 5 = -405

g(-100) = 4 * (-100 - 5) = -420

h(-100) = -100/4 - 5 = -30

Hence, the function value that is largest is h(-100)

At x = 1/100, we have:

f(1/100) = 4/100 - 5 = -4.96

g(1/100) = 4 * (1/100 - 5) = -19.96

h(1/100) = (1/100)/4 - 5 = -4.9975

Hence, the function value that is largest is f(1/100)

Read more about linear functions at:

brainly.com/question/15602982

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The perimeter of a rhombus is 180 cm and one of its diagonals is 72 cm. Find the length of the other diagonal and area of the rh
rewona [7]

Hi there! :)

<u>Answer:</u>

Length of the second diagonal: 54 cm

Area of the rhombus: 1,944 cm²


Step-by-step explanation:

1) To find the value of the second diagonal, you first need to know some important properties of rhombuses:

Since the perimeter is 180, and by definition a rhombus has four congruent sides (of equal length), each side length of the rhombus is equal to 45.

The diagonals of rhombuses also form four right triangles, with hypotenuses equal to the side length of the rhombus and legs equal to half the lengths of the diagonals. In this case one hypotenuse would be equal to 45 and one leg would be equal to 36 (72 ÷ 2 = 36).

We can therefore use the Pythagorean Theorem to solve for one-half of the unknown diagonal:

c² = a² + b² → Where "c" is the hypotenus & "a" and "b" are the two other sides.

<u>45² = 36² + b²</u> → Where "b" is the half of the unknown diagonal.

We can now solve this equation for "b":

<u>45²</u> = <u>36²</u> + b²

45² = <u>2,025</u>

36² = <u>1,296</u>

2,025 = <u>1,296</u> + b²

Subtract "1,296" from each side of the equation → 2,025 - 1,296 = <u>729</u>

729 = b<u>²</u>

Square root on each side of the equation → √729 = <u>27</u>

<u>27 = b</u>

Since "b" represents half of the unknown diagonal, we need to multiply by 2 to find the full length of the diagonal:

27 × 2 = <u>54 ⇒ Length of the other diagonal.</u>


2) To find the area of the rhombus, you need to multiply the length of the 2 diagonals and divide the answer by 2:

<u>(72 × 54)</u> ÷ 2 = A

Multiply "72" & "54" together → 72 × 54 = <u>3,888</u>

<u>3,888 ÷ 2</u> = A

<u>1,944 = A</u>


There you go! I really hope this helped, if there's anything just let me know! :)

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3 years ago
Find the equation of the vertical line through (7,-3)
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X = 7
Is a vertical line that passes through (7,-3).
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3 years ago
Im really bad at this haha
expeople1 [14]
The correct answer is B
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3 years ago
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At the local nursery, 1/4 of the plants for sale are flowers and another 3/5 of them are bushes. What fraction of the plants for
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Answer:

17/20

Step-by-step explanation:

1/4 +3/5 simplify into:

5/20 + 12/20= 17/20

5 0
2 years ago
A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in
Andreyy89
So, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

\bf \begin{array}{ccllll}&#10;rate&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{1}{6}&100\\\\&#10;\frac{1}{5}&x&#10;\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}&#10;\\\\\\&#10;x=\cfrac{6\cdot 100}{5}\implies x=120

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
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3 years ago
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