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Paha777 [63]
2 years ago
14

4. Here are the equations that define three functions.

Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

The functions f(x), g(x) and h(x) are all linear functions

  • The function value that is largest is h(-100)
  • The function value that is largest is h(-100)
  • The function value that is largest is f(1/100)

<h3>How to determine the function with the largest values</h3>

The functions are given as:

f(x) = 4x - 5

g(x) = 4(x - 5)

h(x) = x/4 -5

At x = 100, we have:

f(100) = 4 * 100 - 5 = 395

g(100) = 4 * (100 - 5) = 380

h(100) = 100/4 - 5 = 20

Hence, the function value that is largest is f(100)

At x = -100, we have:

f(-100) = -4 * 100 - 5 = -405

g(-100) = 4 * (-100 - 5) = -420

h(-100) = -100/4 - 5 = -30

Hence, the function value that is largest is h(-100)

At x = 1/100, we have:

f(1/100) = 4/100 - 5 = -4.96

g(1/100) = 4 * (1/100 - 5) = -19.96

h(1/100) = (1/100)/4 - 5 = -4.9975

Hence, the function value that is largest is f(1/100)

Read more about linear functions at:

brainly.com/question/15602982

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Many times business will raise the prices of their goods
hjlf

The price that will maximize profit is $ 5.50.

Since an auditorium has seats for 1200 people, and for the past several days, the auditorium has been filled to capacity for each show, and tickets currently cost $ 5.00 and the owner wants to increase the ticket prices, and he estimates that for each $ 0.50 increase in price, 100 fewer people will attend, to determine which is the price that will maximize profit, the following calculation must be made:

  • 1200 x 5 = 6000
  • 1100 x 5.5 = 6050
  • 1000 x 6 = 6000

Therefore, the price that will maximize profit is $ 5.50.

Learn more in brainly.com/question/25313241

7 0
2 years ago
Please I need some answers one or two are fine
Svetlanka [38]

Answer:

A. 10,000

B. 1,000,000

C. 10,000,000,000

D. 1,000,000,000,000

Step-by-step explanation:

10,000/ 10∧4 = 1

1,000,000/ 10∧6 = 1

10,000,000,000/ 10∧10 = 1

1,000,000,000,000/ 10∧12 = 1

Hope this helps! Good luck!

7 0
3 years ago
Round 13,046 to the nearest thousand.
Margaret [11]

Answer:

13,000

Step-by-step explanation:

When rounding, first:

Find the place value that you are looking for, in this case, being the thousands place value. It is a 3:

1<u>3</u>,046

When you round, you will look at the place value directly next to the one you are trying to find (which is the thousands place value). In this case, it will be the hundreds place value, which has the value of 0.

When the value of the number is 5 or greater, you round up.

When the value of the number is 4 or less, you round down.

In this case, it is 0, which is less than 4, so you round down.

13,046 to the nearest thousand place value is 13,000.

~

8 0
2 years ago
Read 2 more answers
What is the solution to the system of linear equations below? 2/5x−y=6 −2x+5y=−30 Select one: A. (-13, 14) B. (-5, -8) C. no sol
tester [92]

Answer:

D. Infinitely many solutions

Step-by-step explanation:

-\frac{2}{5}x-y=6      |  -2x+5y=-30

1.Since neither equation contains an isolated. However, we can isolate -y in the first equation by adding \frac{2}{5}x to both sides.

Like this: \frac{2}{5}x-\frac{2}{5}x-y=6-\frac{2}{5}x

ending up with y=6-\frac{2}{5}x

2.Now, we can change y to a positive y. By doing so, we divide -y by the entire equation.

Like this \frac{-y=6-\frac{2}{5}x }{-y}

Ending with y=-6+\frac{2}{5}x

3.Now, we can plug the expression -6+\frac{2}{5}x into the second equation as a substitute for y, and solve for x. Then, we can use x to calculate y.

Like this -2x+5(-6+\frac{2}{5}x)=-30\\ -2x-30+2x=-30\\

4. Since -2x+2x would cancel out and leave -30=-30. This is true because we know -30 equals -30 with no variable in sight.

3 0
3 years ago
A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

50 = 200 + C  ==>  C = -150

so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0
3 years ago
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