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Orlov [11]
3 years ago
13

A car is traveling at a speed of 81 kilometers per hour. What is the car's speed in meters per second? How many meters will the

car travel in 20 seconds? Do not round your answers.
Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

450meters

Step-by-step explanation:

Given data

Speed = 81km per hour

Let us convert to meter per seconds

1 km= 1000m

1 hour=3600 seconds

= 1000/3600= 5/18 m/s

=81*5/18

=405/18

=22.5 m/s

Hence the distance traveled in 20 seconds is

distance= speed*time

distance= 22.5*20

distance= 450 meters

Hence the distance is 450meters

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The answer is Joel earns $7 per hour to mow his aunt’s lawn. If he spends $6 on gas, how many hours, x, will he need to mow to have $29 left?

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3 years ago
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Solnce55 [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

6 0
3 years ago
Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to do its route and bus B takes 35 minutes to complete its r
DaniilM [7]

Answer:

8:30 pm

Step-by-step explanation:

step 1

Decompose the numbers in prime factors

30=(2)(3)(5)\\35=(5)(7)

step 2

Find the LCM

The LCM of 30 min and 35 minutes will be given as

LCM=(2)(3)(5)(7)=210\ min

step 3

Adds 210 minutes to the starting time

First, converting 210 minutes to hours

Remember that

1\ h=60\ min

will need dividing 210 by 60

210/60=3.5\ h

therefore

5:00 pm+3.5 h=8:30 pm

7 0
4 years ago
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