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2 years ago

I need help pleaseeeeeeeeee

Mathematics

2 answers:

Katyanochek1 [597]2 years ago

7 0

Answer: ba

Step-by-step explanation:

nika2105 [10]2 years ago

3 0

Answer:

Step-by-step explanation:

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The endpoints of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the Pentagon?

ryzh [129]

the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}$

4 0

2 years ago

Olivia ordered 24 cupcakes and a layer of cake. The layer cost $16 and the total cost of the order was $52. What was the price o

ArbitrLikvidat [17]

$16 was only for the layer.
$52-$16= cost of the cupcakes in total.
$36=cost of all cupcakes
36/24= cost of one cupcake
1.5= cost of one cupcake

each cupcake costs $1.50

4 0

3 years ago

Read 2 more answers

I need help with this pls

Vilka [71]

Each chore he completed he gets $3

so 5 x 3 = 15

answer is 15

8 0

3 years ago

Read 2 more answers

g Consider the experiment of a single roll of an honest die and a single toss of 3 fair coins. Let X be the value on the die and

klemol [59]

Answer:

The probability function of X and Y is

$P(X = k, Y = 0) = 1/48\\P(X = k, Y = 1) = 1/16\\P(X = k, Y = 2) = 1/16\\P(X = k, Y = 3) = 1/48$

With k in {1,2,3,4,5,6}

Step-by-step explanation:

We can naturally assume that X and Y are independent. Because of that, P(X=a, Y=b) = P(X=a) * P(Y=b) for any a, b.

Note that, since the die is honest, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. We can conclude as a consequence that P(X=k, Y=l) = P(Y=l)/6 for any k in {1,2,3,4,5,6}.

Y has a binomial distribution, with parameters n = 3, p = 1/2. Y has range {0,1,2,3}. Lets compute the probability mass function of Y:

$P_Y(0) = {3 \choose 0} * 0.5^3 = 1/8$

$P_Y(1) = {3 \choose 1} * 0.5* 0.5^2 = 3/8$

$P_Y(2) = {3 \choose 2} * 0.5^2*0.5 = 3/8$

$P_Y(3) = {3 \choose 3} * 0.5^3 = 1/8$

Thus, we can conclude that the joint probability function is given by the following formula

$P(X = k, Y = 0) = 1/8 * 1/6 = 1/48\\P(X = k, Y = 1) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 2) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 3) = 1/8 * 1/6 = 1/48$

For any k in {0,1,2,3,4,5,6}

4 0

3 years ago

"A sample of 30 randomly selected oranges was taken from a large population, and their diameters were measured. The mean diamete

Yuki888 [10]

Answer:

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.075 = 0.925$ , so $z = 1.44$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.44*\frac{8}{\sqrt{30}} = 2.1$

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.

The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

6 0

2 years ago