Answer:
Yes, Mina is correct
Step-by-step explanation:
Let the triangles be A and B
Given
Triangle A:

Triangle B:

Required
Is Mina's claim correct?
First, we calculate the third angle in both triangles.
For A:


For B:


For triangle A, the angles are: 34, 57 and 89
For triangle B, the angles are: 34, 57 and 89
<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>
Answer:
y=81x^4+648x^3+1944x^2+2592x+1289
Step-by-step explanation:
1. Interchange x and y.
- y=\frac{\sqrt[4]{x+7}}{3}-2
- x=\frac{\sqrt[4]{y+7}}{3}-2
2. Then solve x=\frac{\sqrt[4]{y+7}}{3}-2 for y.
3. y=81x^4+648x^3+1944x^2+2592x+1289
I hope this helps.
4.5x + 1.5y = 24 ⇒ 4.5x + 1.5y = 24
1.0x - 1.0y = 4 ⇒<u> 4.5x - 4.5y = 18</u>
<u>6y</u> = <u>6</u>
6 6
y = 1
4.5x + 1.5(1) = 24
4.5x + 1.5 = 24
<u> - 1.5 - 1.5</u>
<u>4.5x</u> = <u>22.5</u>
4.5 4.5
x = 5
(x, y) = (5, 1)
Answer:
D
Step-by-step explanation:
a- Multiply the square of 7/2 by 3.14
b-Multiply 36 and 36
c-Multiply 7 and 7
d-Multiply the square of 36 by 3.14
Answer:
go on the y-axis and find line 8. draw a line from one side of the graph to the other going through 8. then shade everything BELOW the line. #markasbrainliest