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juin [17]
3 years ago
5

How do I solve 3(x+5)=39

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
5 0
3 times x
3 times 5
3x+15=39
Subtract 15 from 39
39-15=24
3x=24
24:3=8
X=8
azamat3 years ago
4 0
3(x+5)=39

3 * x + 3 * 5 = 39

3x + 15 = 39

3x = 39 - 15

3x= 24
x = 8


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Please help me<br><br> I don’t understand it
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Answer:

D

Step-by-step explanation:

The solution is B. In each equation, it uses parenthesis to group operations. On the left, each pair repeats one number either 1.6 and 4.2. On the right is written the reduced form by writing the expression with a greatest common factor.

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Option B is incorrect because the operation in the parenthesis is multiplication and not addition.

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4 years ago
If x + y = 2 and x - y = 6, solve for x and y.
anyanavicka [17]

Answer:

Step-by-step explanation:

Givens

x + y = 2

x - y = 6

Solution

Just add the two equations together. The y's will drop out.

x + y = 2

<u>x - y = 6 </u>             Add

2x = 8                 Divide by 2

2x/2 = 8/2          Combine

x = 4                   Substitute x = 4 into the top equation

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7 0
2 years ago
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iren2701 [21]

Answer:  The correct answer is:  " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate:  log 2 base 8 .

_______________________________

Rewrite as:  " log_2}8 = ? _______________  " ;  log_2}8 = ? _______________

_______________________

Take note of the following definition of a logarithm:

_______________________

"   log_{m}n = a " ;  ↔  " m^{a} =n  "  ;

_______________________

in which:  m  refers to the "base" ;

               n  refers to the "argument" ;

               a  refers to the "exponent" ;

______________________________

As such:

       " log_2}8 = ? _______________ "

      ⇔ " 2^{x} = 8 " ; Solve for "x" ;  

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 Note:  

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 → " 2^{x} = 8 " ;

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 → as such:   " x = 3  " ;

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Thus:

"log 2 base 8 " ;

          = log{_{2}}8 = 3  .

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Hope this helps!

Best wishes to you!

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