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kiruha [24]
2 years ago
12

Help me find the range and width!

Mathematics
1 answer:
Alik [6]2 years ago
8 0
The range of the data is 93
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(12,-9) and (-2,-2) in slope intercept form and if u want the points please explain how u got it
Montano1993 [528]

Answer:

y= -\frac{1}{2} x-3

Step-by-step explanation:

Slope intercept form :

y = mx + b

m is the slope

b is the y-intercept

Let's look for m, use the formula \frac{(y_{1}-y_{2} ) }{(x_{1} -x_{2} )} to determine it.

\frac{-9 - (-2)}{12 - (-2)} = -\frac{1}{2}

y = -\frac{1}{2}x+b

Now find b, we simply need to plug in one of our coordinates to get our answer.

(12, -9)

-9=-\frac{1}{2} (12)+b

Solve for b :

-9 = -6 + b

-3 = b

b = -3

Our slope intercept is :

y = -\frac{1}{2}x - 3

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2 years ago
The marginal cost of drilling an oil well depends on the depth at which you are drilling; drilling becomes more expensive, per m
sukhopar [10]

Answer:

4,250,000 riyals

Step-by-step explanation:

The total cost of drilling a 500-meter well is the sum of fixed costs (1,000,000 riyals) and variable costs.

By integrating the marginal cost function we get the variable costs function. Evaluating the variable costs function from 0 to 500 meters, gives us the total variable cost.

C(x) =\int\limits^{500}_0 {C(x')} \, dx  =\int\limits^{500}_0 {(4000 + 10x)} \, dx \\C(x)=4000x +5x^2 +c|^{500}_0\\C(500) - C(0) = (4000*500 +5*500^2 +c) - (4000*0 +5*0^2 +c)\\C(500) - C(0) = 3,250,000

Total cost of drilling is:

TC = 3,250,000 + 1,000,000\\TC = 4,250,000\ riyals

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3 years ago
Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together the
posledela
Let's call x1: The rate per hour of the number one mechanic. X2: The rate per hour of mechanic number two. The first thing you should do is identify the system of equations that best describes the problem. In this case it is a system of 2 equations with two unknowns which when solved gives a total of x1 = 85 $ / h and x2 = 50 $ / h. Attached solution.

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