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3 years ago

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In the diagram, polygon ABCD is flipped over a line of reflection to form a polygon with its vertices at A′, B′, C′, and D′. Poi

nts A′, B′, and D′ are shown, but the line of reflection and point C′ are not. The line of reflection is , and the coordinates of C′ are . NextReset

1 answer:

Nataliya [291]3 years ago

7 0

Here is what I found

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When multiplying a number by 10, move the decimal to the right. When multiplying a number by 0.1, move the decimal to the left.

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Answer: 0.01 x 10 = .1

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Step-by-step explanation:

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2 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7B36%7D%7B4%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ \frac{36}{4}

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Step-by-step explanation:

$\sqrt{36/4} =$ $\sqrt{36} /\sqrt{4}$

$\sqrt{36}=6$

$\sqrt{4} =2$

6/2=3

Hope that helps :)

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3 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

3 years ago