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Klio2033 [76]
2 years ago
6

Lobe-finned fishes were present in the oceans of the world approximately 400 million years ago. The first tetrapods (vertebrates

that had limbs and could move on land) date to about 365 million years ago. One hypothesis states that early tetrapods evolved from lobe-finned fishes. What is the best plan for testing this hypothesis?
Mathematics
1 answer:
erma4kov [3.2K]2 years ago
7 0

Answer:

<u>comparing the arrangements of bones in the fins of lobe-finned fishes and limbs of the earliest tetrapods.</u>

Step-by-step explanation:

Based on the modern method of archeological findings used, it is the view of some scientists that the best plan to test the hypothesis (assumption) that early tetrapods <em>might</em> have evolved from lobe-finned fishes involves <u>comparing the arrangements of bones in the fins of lobe-finned fishes and limbs of the earliest tetrapods.</u>

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3 years ago
Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r
slamgirl [31]

Will ran the longest

He ran for 56.57 yards, 13.56 yards longer than James.

Step-by-step explanation:

Step 1 :

Will ran the diagonal across a square field measuring 40 yards in each side.

The diagonal of a square can be obtained by the square root of the sum of the squares of its 2 sides [Because it forms the hypotenuse of a right angle triangle]

Hence when the side is 40 yards , the diagonal would be

\sqrt{40^{2} + 40^{2}}  = \sqrt{1600 + 1600}   = \sqrt{3200}  =56.57 yards

So Will ran for 56.57 yards

Step 2 :

James ran the diagonal of a rectangular field with 25 yards length and 35 yards width.

The diagonal of the rectangle can be obtained by the square root of the sum of squares of its length and width.

Hence when the length is 25 yards and width is 35 , the diagonal would be

\sqrt{35^{2} + 25^{2}}  = \sqrt{1225 + 625}} = \sqrt{1850} = 43.01 yards

So James ran for 43.01 yards

Step 3 :

Will ran for 56.57 yards and 43.01 yards.

Hence Will ran for longer distance of 56.57 yards, which is 13.56 yards more than James.

5 0
3 years ago
(4, -2), y = –2x + 3<br><br> PLS HELP HOW DO I DO THIS?
Alex787 [66]

It looks like your instructor wants you to write in point-slope form.

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2 years ago
In a downtown parking lot there are 5 times as many cars there as trucks. There are 12 trucks in the parking lot. How many cars
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7 0
3 years ago
Read 2 more answers
What is the length of segment AE?
nexus9112 [7]

Answer:

AE=\frac{50}{3}\ units

Step-by-step explanation:

step 1

In the right triangle ABC

Applying the Pythagoras Theorem fin the hypotenuse AC

AC^{2} =AB^{2}+BC^{2}

substitute

AC^{2} =6^{2}+8^{2}

AC^{2} =100

AC =10\ units

step 2

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

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\frac{AB}{CD}=\frac{AC}{CE}

substitute and solve for CE

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step 3

Find the length of segment AE

AE=AC+CE

substitute the values

AE=10\ units+\frac{20}{3}\ units=\frac{50}{3}\ units

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3 years ago
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