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o-na [289]
3 years ago
10

Help!!!!! This is only a review!!!!!! Question is on image below.

Mathematics
1 answer:
solmaris [256]3 years ago
6 0
No, the ratios aren’t equivalent
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26,862÷407= <br> PLZZZZ HELPPP
tino4ka555 [31]
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2 years ago
Please help me with this question
-Dominant- [34]

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Step-by-step explanation:

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I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
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Similarly, using
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we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
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Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
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Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)] and select the correct answer below.
Alexxx [7]
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zubka84 [21]

Answer:

70.7

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I put it all together and got 70.7106781187 i cut it

to 70.7

6 0
3 years ago
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